Series, parallel and electrical power
The rules for current, voltage and resistance in series and parallel circuits, calculating with Ohm's law in each, electrical power P = VI, energy in kilowatt-hours and the cost of running appliances, how a house is wired, and how fuses, circuit breakers and safety switches protect you.
Every power point in your house is wired in parallel, so you can switch off the TV without plunging the kitchen into darkness. But plug a kettle, a toaster and a fan heater into one power board and something clicks off. The rules of series and parallel circuits explain both.
Series circuits
In a series circuit the components are connected one after another in a single loop, so the charge has only one path.
- Current is the same everywhere in the loop: I = I₁ = I₂.
- The voltages across the components add up to the supply voltage: V = V₁ + V₂. Each coulomb gives some of its energy to each component in turn. The bigger resistor gets the bigger share of the voltage.
- Resistances add: R = R₁ + R₂. Adding another component in series increases the total resistance, so the current falls.
- If one component breaks, the circuit is broken and everything stops (like old strings of Christmas lights).
Parallel circuits
In a parallel circuit each component is on its own branch, so the charge splits at a junction and rejoins afterwards.
- The voltage across each branch is the same as the supply: V = V₁ = V₂. Every coulomb gets the full energy, whichever branch it takes.
- The branch currents add up to the total current: I = I₁ + I₂. More current flows through the branch with less resistance.
- Adding a branch lowers the total resistance, because it opens another path. The total is always less than the smallest branch resistance. For two branches: 1/R = 1/R₁ + 1/R₂.
- Each branch can be switched on and off on its own, and if one breaks the others keep working. That's why houses are wired in parallel.
A 4 Ω and a 2 Ω resistor are joined in series to a 12 V battery. Total R = 4 + 2 = 6 Ω. Current I = V ÷ R = 12 ÷ 6 = 2 A everywhere.
V₁ = I R₁ = 2 × 4 = 8 V; V₂ = 2 × 2 = 4 V. Check: 8 + 4 = 12 V ✓. The bigger resistor takes the bigger share.
A 6 Ω and a 12 Ω resistor are joined in parallel to the same 12 V battery. Each has the full 12 V across it. I₁ = 12 ÷ 6 = 2 A; I₂ = 12 ÷ 12 = 1 A.
Total current = 2 + 1 = 3 A, so total resistance = 12 ÷ 3 = 4 Ω, less than either branch. Check: 1/6 + 1/12 = 3/12 = 1/4 ✓.
- In Series, set R₁ = R₂. How is the battery voltage shared? Now make R₁ three times R₂.
- Predict the current before you look, using I = V ÷ (R₁ + R₂). Check your answer.
- Switch to Parallel. What do the two voltmeters read? Which branch gets more current?
- In parallel, check that A₁ + A₂ = A for several settings.
- With the same two resistors, which arrangement draws more current from the battery? Which would flatten the battery faster?
Electrical power
Power is the rate of transferring energy, measured in watts (W). One watt is one joule per second. Because voltage is energy per coulomb and current is coulombs per second, multiplying them gives energy per second:
power (W) = voltage (V) × current (A)
P = V I
The energy an appliance uses depends on its power and how long it runs. Electricity companies measure it in kilowatt-hours (kWh): the energy used by a 1000 W appliance running for one hour. 1 kWh = 3 600 000 J.
energy (kWh) = power (kW) × time (h)
cost = energy (kWh) × price per kWh
Household electricity in NSW typically costs around 30 to 40 cents per kWh in 2025–26 (it has risen a lot since the 20 cents often quoted in older textbooks). Rooftop solar owners are paid much less, often 5 cents or under, for electricity they export.
A 2200 W kettle runs on 230 V. I = P ÷ V = 2200 ÷ 230 = 9.6 A, close to the 10 A limit of a normal power point.
It boils for 3 minutes = 0.05 h. Energy = 2.2 kW × 0.05 h = 0.11 kWh.
At 33 c per kWh: 0.11 × 33 = 3.6 cents per boil.
A 10 W LED lamp left on for 11 hours uses the same 0.11 kWh. High-power heating appliances use far more energy than electronics.
How a house is wired
- Electricity arrives at the switchboard, where the meter records the kWh used.
- Each circuit has a circuit breaker. If too much current flows (an overload or a short circuit), the wires would overheat and could start a fire, so the breaker switches off automatically. Older houses use fuses: thin wires that melt and break the circuit.
- The active wire (brown, or red in old houses) carries the 230 V supply. The neutral wire (blue, or black in old houses) completes the circuit. The earth wire (green and yellow) connects metal cases to the ground, so if a fault makes the case live, current flows safely to earth and trips the breaker.
- A safety switch (residual current device, RCD) compares the current in the active and neutral wires. If they differ by even 30 mA, some current must be leaking, perhaps through a person, and it cuts the power in about 30 milliseconds, fast enough to prevent a fatal shock. RCDs are required on new homes in Australia and have saved many lives. Press the test button every few months.
Electrical work in Australia must be done by a licensed electrician. Never use appliances near water, never poke anything into a power point, and stay at least 8 metres away from fallen power lines.
- Plug in a phone charger, a laptop and a TV. Calculate the total current using I = P ÷ V and check the gauge.
- Unplug everything and plug in just the kettle. How close are you to the 10 A limit?
- Now add the toaster. What happens, and why is this a safety feature rather than a fault? Press Reset the board after unplugging something.
- Find the largest number of appliances you can run at once without tripping the board.
- Which appliance costs most per hour to run? Why do heating appliances need so much power?
Test yourself
A 10 Ω and a 20 Ω resistor are in series with a 6 V battery. The current is
R = 10 + 20 = 30 Ω; I = 6 ÷ 30 = 0.2 A.
In the same circuit, the voltage across the 20 Ω resistor is
V = I R = 0.2 × 20 = 4 V (and 2 V across the 10 Ω: 4 + 2 = 6 V).
Two lamps are in parallel with a 12 V battery. One draws 0.5 A and the other 1.5 A. The current from the battery is
Branch currents add: 0.5 + 1.5 = 2.0 A.
A 1500 W heater runs for 4 hours at 30 c per kWh. It costs
1.5 kW × 4 h = 6 kWh; 6 × 30 c = 180 c = $1.80.
The device that cuts the power when current leaks to earth through a person is
An RCD detects a difference between active and neutral currents as small as 30 mA.
Label the parts of the household wiring.
Which type of circuit does each statement describe?
Power is measured in and is calculated by multiplying voltage by . Electricity bills measure energy in . The green and yellow wire is the wire. A switches off when too much current flows.
A student plugs a 2200 W kettle, a 900 W toaster and a 120 W TV into one power board rated at 10 A on a 230 V supply. Calculate the total current, explain what will happen and why, and explain why the appliances are connected in parallel rather than series.
The total power is 2200 + 900 + 120 = 3220 W. The current is I = P ÷ V = 3220 ÷ 230 = 14 A. This is more than the 10 A rating of the board, so its overload switch (or the circuit breaker at the switchboard) will trip and cut the power. This is a safety feature: too much current would make the wires overheat, which could melt the insulation and start a fire. The appliances are connected in parallel so that each one gets the full 230 V it was designed for, and each can be switched on and off on its own. In series the 230 V would be shared between them, so none would work properly, and if one were switched off or failed, they would all stop.
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