Reflection, refraction and diffraction
How mechanical waves behave at barriers, boundaries and gaps: the law of reflection, refraction as a change of speed with the frequency fixed, diffraction and how it depends on gap size compared with wavelength, all modelled with wavefronts and rays in a ripple tank.
Stand behind a big rock on the beach and the waves still curl around to reach you. Stand at the end of a breakwater and the swell turns as it runs into shallower water, so that by the time it reaches the sand it is almost parallel to the shore, whatever direction it came from. Both effects come from the same simple rule: a wave's speed depends on the medium, and every point on a wavefront acts as a new source.
Wavefronts and rays
To draw waves in two dimensions we use two pictures together:
- A wavefront is a line joining points that are in phase, such as a line along a crest. Neighbouring wavefronts are one wavelength apart.
- A ray is an arrow showing the direction the wave (and its energy) travels. Rays are always at right angles to the wavefronts.
A ripple tank shows these clearly. A light above the tank makes each crest act like a small lens, so crests appear as bright lines on a screen below. A straight bar dipping into the water makes straight (plane) wavefronts; a point dipper makes circular ones.
Reflection
When a wave meets a barrier it bounces back. Angles are measured between the ray and the normal, a line at right angles to the surface at the point where the ray hits.
$\theta_i = \theta_r$
The incident ray, reflected ray and normal all lie in the same plane. Reflection changes only the direction: the wave stays in the same medium, so its speed, frequency and wavelength are unchanged.
Echoes, sonar and ultrasound imaging all use reflection. A wave can reflect from any boundary where the medium changes, not just a hard wall: some ultrasound reflects at every boundary between tissues, which is how the image is built up.
Refraction
Refraction is the change in direction of a wave as it passes from one medium into another at an angle, caused by the change in speed. In a ripple tank, water waves travel more slowly in shallow water, so a sheet of glass on the tank floor makes a shallow region.
The reasoning HSC markers look for runs like this:
- The frequency is set by the source, so it is the same on both sides of the boundary.
- The speed changes because the medium changes.
- From $\lambda = v/f$, the wavelength changes in proportion to the speed.
- If the wavefront meets the boundary at an angle, the part that crosses first changes speed first, so the wavefront swings round and the direction changes.
Slowing down bends the ray towards the normal; speeding up bends it away from the normal. A wave that hits the boundary along the normal changes speed and wavelength but not direction. The same rule, with numbers, is Snell's law: $\dfrac{\sin\theta_1}{\sin\theta_2} = \dfrac{v_1}{v_2}$. You will use it for light on page 3H.
Ripple-tank waves of frequency 8.0 Hz have a wavelength of 2.5 cm in deep water. They pass into shallow water where their speed is 12 cm/s. (a) Find the speed in the deep water. (b) Find the wavelength in the shallow water. (c) The waves meet the boundary at 50° to the normal. Find the angle of refraction.
Refraction explains why waves line up with the beach. The part of each wavefront in shallower water slows first, so the whole front swings round until it runs almost parallel to the depth contours. Headlands get concentrated wave energy and bays get less, which is why surf breaks form off points.
Diffraction
Diffraction is the spreading of a wave as it passes through a gap or around the edge of an obstacle. Each point on a wavefront that gets through the gap acts as a source of new circular wavelets (Huygens' principle, which you will use again in Year 12), so the wave fans out into the region behind the barrier.
The amount of spreading depends on the ratio of wavelength to gap width:
- Gap much wider than $\lambda$: the wave passes almost straight through with a sharp "shadow" and only a little bending at the edges.
- Gap about equal to $\lambda$ or smaller: the wave spreads out in almost semicircular wavefronts.
Diffraction does not change the wave's speed, frequency or wavelength. It explains why you can hear someone around a corner but cannot see them: sound wavelengths (about 0.02 to 17 m) are comparable to doorways, while light wavelengths (about 400 to 700 nm) are millions of times smaller. It also explains why long-wavelength AM radio reaches valleys behind hills that FM signals miss.
Swell with a wavelength of 60 m reaches a harbour mouth. Compare a 50 m gap with a 400 m gap.
- In Refraction mode at the start (40°, speed ratio 0.60, deep to shallow) the readouts show θ₂ = 22.7°, λ₁ = 10 mm and λ₂ = 6 mm. Check: sin 40° × 0.60 = sin 22.7°.
- Switch to Shallow → deep. At 30° the wave bends away to 56.4°. Raise the angle past 36.9° and the refracted wave disappears: total internal reflection.
- In Diffraction mode set the gap to 2.0 wavelengths: the first quiet direction is at 30°. Now set the gap to 1.0 wavelength and describe the wavefronts.
- In Reflection mode, change the angle of incidence and press Send a wave train. Does the reflected train have a different wavelength?
Test yourself
Water waves pass from deep water into shallow water. Which row describes the changes?
Shallow water slows the waves. The frequency is fixed by the source, so $\lambda = v/f$ decreases.
Sound from a band in a hall can be heard clearly through an open doorway by people standing well to the side of it. The main reason is that
Strong diffraction happens when the gap is comparable to the wavelength. Typical sound wavelengths are 0.1 to 3 m, like a doorway.
A plane wave strikes a straight barrier with its wavefronts at 35° to the barrier. The angle of reflection, measured from the normal, is
The ray is perpendicular to the wavefront and the normal is perpendicular to the barrier, so the angle between the ray and the normal equals the angle between the wavefront and the barrier: 35°. Then $\theta_r = \theta_i = 35°$.
Waves of wavelength 3.0 cm travel at 15 cm/s in a ripple tank. They reach a region where their speed is 10 cm/s. Their wavelength there is
$f = 15/3.0 = 5.0$ Hz, unchanged. $\lambda_2 = 10/5.0 = 2.0$ cm.
Label the refraction diagram.
Order the steps of the explanation for refraction.
Angles in wave diagrams are measured from the . When a wave slows down at a boundary it bends the normal, and its gets shorter. Diffraction is greatest when the gap is about the same size as the . Diffraction does not change the wave's .
Ocean swell approaches a straight beach at an angle, from deep water where it travels at 12 m/s with a wavelength of 96 m. Near the shore the water is shallow and the speed drops to 4.0 m/s. (a) Calculate the frequency and the wavelength near the shore. (b) Explain, using a wavefront model, why waves arrive almost parallel to the beach. (c) Explain why a headland sticking out from the beach receives larger waves than a bay.
(a) $f = v/\lambda = 12/96 = 0.125$ Hz (a period of 8.0 s). The frequency does not change, so near the shore $\lambda = v/f = 4.0/0.125 = 32$ m.
(b) A wavefront approaching at an angle has one end in shallower water than the other. That end slows down first, while the deeper end keeps moving faster, so the wavefront swings round. The ray bends towards the normal to the depth contours, and by the time the front reaches the sand it is nearly parallel to the beach.
(c) The water is shallower off a headland than in the bay next to it. Wavefronts slow down over the shallow water in front of the headland and wrap around it, so the rays bend in towards the headland from both sides and the energy converges there. In the bay the rays spread apart, so the same energy is shared along a longer stretch of shore and the waves are smaller.
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