NMR spectroscopy
How nuclear magnetic resonance works, chemical shift, carbon-13 NMR for counting carbon environments, and proton NMR with chemical shift, integration and splitting (the n + 1 rule).
If you've ever had an MRI scan, you've been inside an NMR machine. The scanner uses a powerful magnet and radio waves to detect the hydrogen nuclei in the water and fat of your body, building an image of soft tissue without any X-rays. Chemists use the same physics on a few milligrams of a compound in a narrow glass tube, and it tells them, almost atom by atom, how the molecule is put together.
How NMR works
Some nuclei, including ¹H and ¹³C (but not ¹²C or ¹⁶O), behave like tiny magnets because they have a property called spin. In a strong external magnetic field they line up either with the field (lower energy) or against it (higher energy). Radio-frequency radiation with an energy equal to the gap, $\Delta E = hf$, is absorbed and flips nuclei to the higher state. This absorption is resonance.
The key to NMR is that $\Delta E$ depends slightly on the electrons around each nucleus. Electrons create a small magnetic field that opposes the external one, shielding the nucleus. A nearby electronegative atom (O, N, Cl) or a C=O group pulls electron density away, deshielding the nucleus so it absorbs at a higher frequency. Nuclei in different chemical environments therefore give separate signals.
Modern NMR spectrometers use superconducting magnets cooled by liquid helium, with fields of about 9–23 tesla. They are described by the frequency at which ¹H resonates: research instruments of 400–800 MHz are standard and the largest exceed 1 GHz. (Older textbooks describe 60–300 MHz instruments, which are now mainly used for teaching.) The sample is dissolved in a solvent with no ordinary hydrogen atoms, such as CDCl₃, so the solvent doesn't swamp the spectrum.
Chemical shift
Signals are plotted against chemical shift, $\delta$, in parts per million (ppm), measured from the signal of a reference compound, tetramethylsilane (TMS, Si(CH₃)₄), which is set to 0. TMS is used because its 12 identical hydrogens and 4 identical carbons give one strong signal, it is unreactive, and its nuclei are more shielded than almost any in an organic molecule. Because $\delta$ is a ratio, the same compound gives the same shifts on any instrument. The scale runs from right (0) to left (larger $\delta$, more deshielded).
Carbon-13 NMR
Only about 1.1% of carbon atoms are ¹³C, so ¹³C spectra are weaker and are usually recorded so that each carbon environment gives a single line. A ¹³C spectrum tells you two things:
- The number of signals = the number of different carbon environments. Carbons related by the molecule's symmetry are equivalent and give one signal.
- The chemical shift of each signal shows what the carbon is bonded to. Typical values (use the data sheet ranges in exams): CH₃ or CH₂ in a chain 5–45 ppm; C bonded to O 50–90 ppm; C=C 110–150 ppm; C=O of acids and esters 160–185 ppm; C=O of aldehydes and ketones 190–220 ppm.
Signal heights in a routine ¹³C spectrum are not proportional to the number of carbons, so you can't count atoms from them.
Proton (¹H) NMR
A ¹H spectrum gives four pieces of information:
- Number of signals: the number of different hydrogen environments.
- Chemical shift: the type of environment. Typical values: H on a carbon in a chain 0.9–1.7 ppm; H on a carbon next to C=O 2.0–2.7 ppm; H on a carbon bonded to O 3.3–4.8 ppm; H on C=C 4.5–7 ppm; aldehyde H 9.4–10 ppm; carboxylic acid H 10–13 ppm; alcohol O–H anywhere from 1 to 6 ppm.
- Relative intensity (integration): the area under each signal is proportional to the number of hydrogens in that environment. Ethanol gives 3 : 2 : 1 for CH₃ : CH₂ : OH.
- Splitting pattern: how many hydrogens are on the neighbouring carbon atoms.
Splitting: the n + 1 rule
The small magnetic fields of hydrogens on the next carbon add to or subtract from the field felt by a hydrogen, splitting its signal into a cluster of peaks. A signal from H atoms with $n$ equivalent H neighbours on adjacent carbons is split into $n + 1$ peaks:
| Neighbouring H (n) | Peaks (n + 1) | Name | Height ratio |
|---|---|---|---|
| 0 | 1 | singlet | 1 |
| 1 | 2 | doublet | 1 : 1 |
| 2 | 3 | triplet | 1 : 2 : 1 |
| 3 | 4 | quartet | 1 : 3 : 3 : 1 |
| 6 | 7 | septet | 1 : 6 : 15 : 20 : 15 : 6 : 1 |
Three useful rules: equivalent hydrogens don't split each other; O–H hydrogens usually appear as a singlet and don't split their neighbours (they exchange rapidly between molecules); and the classic ethyl group, CH₃CH₂–, always shows as a 3H triplet plus a 2H quartet. A 6H doublet with a 1H septet means an isopropyl group, (CH₃)₂CH–.
Predict the ¹H NMR spectrum of ethyl ethanoate, CH₃COOCH₂CH₃.
- For ethanol (¹H), tap each signal. Confirm the triplet at 1.2 ppm (3H), the quartet at 3.7 ppm (2H) and the singlet at 2.6 ppm (1H), and explain each splitting.
- Switch to ¹³C and compare propan-1-ol (3 signals) with propan-2-ol (2 signals). Which carbons are equivalent?
- Look at propan-2-ol's ¹H spectrum. Find the 6H doublet and the 1H septet, and explain both with the n + 1 rule.
- Compare butanone and propanoic acid. Both have an ethyl group, but where does the CH₂ quartet appear in each, and why is there a signal near 12 ppm in only one?
Test yourself
How many signals would appear in the ¹³C NMR spectrum of propanone, CH₃COCH₃?
The two CH₃ carbons are equivalent; the C=O carbon is different.
In the ¹H NMR spectrum of 1-chloropropane, CH₃CH₂CH₂Cl, the signal for the CH₃ hydrogens is a
The neighbouring CH₂ has 2 H, so 2 + 1 = 3 peaks.
Tetramethylsilane is used as the reference in NMR because
All 12 H (and 4 C) are equivalent and well shielded, so TMS gives a single signal at δ = 0.
A compound's ¹H NMR spectrum has a 6H doublet at 1.2 ppm and a 1H septet at 4.0 ppm, plus a 1H singlet. The compound is
Two equivalent CH₃ next to one CH, with the CH on oxygen (4.0 ppm) and an O–H singlet.
Name the splitting pattern of each signal.
In the ¹H NMR spectrum, how is the signal of the named group split?
Chemical shift is measured in relative to TMS. The area under a ¹H signal is proportional to the number of atoms in that environment. A signal from H atoms with three H neighbours is split into a . Electrons around a nucleus it from the external magnetic field.
Explain how ¹H NMR spectroscopy could distinguish between propan-1-ol and propan-2-ol. Refer to the number of signals, integration and splitting.
Propan-1-ol, CH₃CH₂CH₂OH, has four hydrogen environments, so four signals in the ratio 3 : 2 : 2 : 1. The CH₃ (about 0.9 ppm) has two neighbouring H, so it is a triplet. The middle CH₂ has five neighbouring H (3 + 2), so it is split into six peaks (a sextet). The CH₂ bonded to O is deshielded (about 3.6 ppm) and is a triplet from the middle CH₂. The O–H is a singlet.
Propan-2-ol, (CH₃)₂CHOH, has a line of symmetry, so its two CH₃ groups are equivalent: only three signals, in the ratio 6 : 1 : 1. The 6H signal (about 1.2 ppm) is a doublet, because each CH₃ has one neighbouring H. The CH, bonded to O (about 4.0 ppm), has six neighbouring H and is a septet. The O–H is a singlet.
So the number of signals (4 vs 3), the integration ratio and the presence of a 6H doublet and 1H septet clearly identify each isomer.
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