Time dilation and length contraction
The light clock thought experiment, time dilation and proper time, length contraction and proper length, the Lorentz factor, and the experimental evidence from cosmic-ray muons, particle accelerators, atomic clocks flown around the world and GPS.
Every minute, about one muon passes through each square centimetre at sea level, including through you as you read this. Muons are made by cosmic rays hitting the top of the atmosphere about 15 km up, and they live on average only 2.2 millionths of a second. Even at nearly the speed of light, that's only long enough to travel about 660 m. By everyday physics they should all decay long before they reach the ground. They arrive because, as seen from Earth, their clocks run ten times slower.
The light clock
Einstein used thought experiments to work out what his two postulates imply. Imagine a light clock: a pulse of light bouncing between two mirrors a distance $D$ apart. Each round trip is one "tick".
On board a spaceship, the light goes straight up and down. One tick (up only, for simplicity) takes $t_0 = D/c$.
An observer on Earth watches the ship pass at speed $v$. During the tick the ship moves sideways a distance $vt$, so the light follows a diagonal path. By postulate 2 the light still travels at $c$, so the diagonal has length $ct$. By Pythagoras,
$$(ct)^2 = (ct_0)^2 + (vt)^2$$
Solving for $t$:
$$t = \frac{t_0}{\sqrt{1 - \dfrac{v^2}{c^2}}}$$
The Earth observer measures each tick to take longer than the ship observer does. The moving clock runs slow. This is time dilation, and it applies to every process on the ship: atomic clocks, heartbeats, ageing. It is not a fault in the clock; time itself passes differently in the two frames.
Proper time and the Lorentz factor
$t_0$ is the proper time: the time between two events measured by an observer for whom both events happen at the same place, so a single clock can time them. Here, both ends of a tick happen at the same place on the ship. Any other observer measures a longer time $t$, the dilated time.
The factor that appears everywhere in relativity is the Lorentz factor,
$$\gamma = \frac{1}{\sqrt{1 - \dfrac{v^2}{c^2}}}$$
so $t = \gamma t_0$. At everyday speeds $\gamma$ is 1.000 000 000 000 to many decimal places, which is why Newton's physics works so well. It is 1.15 at half the speed of light, 2.3 at 0.9$c$, 7.1 at 0.99$c$, and becomes infinite as $v$ approaches $c$.
A spacecraft travels to a star at 0.80$c$. The astronauts measure the journey as taking 3.0 years. How long does it take as measured from Earth?
Length contraction
If the astronauts' journey takes less time, but both observers agree on the relative speed, the astronauts must measure a shorter distance. A moving object, or a moving distance, is contracted along the direction of motion:
$$l = l_0\sqrt{1 - \frac{v^2}{c^2}}$$
$l_0$ is the proper length: the length measured by an observer at rest relative to the object (or to the two end points). Every observer moving relative to it measures a shorter length $l$. Only lengths parallel to the motion contract; perpendicular dimensions are unchanged.
In the previous example, the star is 4.0 light-years from Earth, measured in Earth's frame. (a) Check the Earth journey time. (b) What distance do the astronauts measure?
A spaceship is 120 m long when at rest. How long is it measured to be by an observer it passes at 0.60$c$?
The evidence
Cosmic-ray muons. Bruno Rossi and David Hall (1941) compared muon counts on a mountain in Colorado and lower down, and found far more surviving than expected. David Frisch and James Smith (1963) did it precisely: on Mount Washington (1910 m) they counted 563 muons per hour in a particular speed range. Without time dilation only about 27 per hour should have reached sea level. They measured about 410, matching time dilation with $\gamma \approx 8.8$.
Muons are created 15 km above the ground moving at 0.995$c$. Their mean lifetime at rest is 2.2 µs. How far does a typical muon travel (a) without relativity, (b) with time dilation? (c) Explain the result in the muon's frame.
Particle accelerators. In 1977 at CERN, muons circling a storage ring at $\gamma = 29.3$ lived for 64.4 µs instead of 2.2 µs, agreeing with time dilation to within 0.1%. Accelerators such as the Large Hadron Collider are designed around relativistic effects every day.
Atomic clocks in aircraft. In 1971 Joseph Hafele and Richard Keating flew caesium atomic clocks around the world on commercial flights, eastward and then westward, and compared them with clocks at the US Naval Observatory. Relative to the ground clocks, the eastward clocks lost 59 ± 10 ns and the westward clocks gained 273 ± 7 ns, agreeing with predictions within the uncertainty. (These figures include a second effect from general relativity: clocks higher in Earth's gravity run faster. Special relativity alone predicts the moving clocks run slow.) In 2010 optical atomic clocks detected time dilation at speeds of just 10 m/s.
GPS. GPS satellites orbit at about 3.9 km/s. Special relativity makes their clocks run slow by about 7 µs per day, while weaker gravity at their altitude makes them run fast by about 45 µs per day. The net 38 µs per day is corrected for in the satellites. Without it, position errors would grow by about 10 km each day.
- Set the ship speed to 0.60. Check γ = 1.250 and the Earth-measured tick of 1.25 ns with $t = t_0/\sqrt{1 - v^2/c^2}$. Check the ship length of 24.0 m with $l = l_0\sqrt{1 - v^2/c^2}$.
- Set 0.80, then 0.99. How do γ, the tick and the length change? At what speed does the moving clock tick at half the rate?
- Switch to Cosmic-ray muons at 0.995c. Compare the distance in one lifetime with and without relativity, and check them against the worked example.
- Compare the fraction reaching the ground with and without relativity. Which panel shows the muon's own view, and what is different about it?
- Try 0.9c and 0.9998c. How sensitive is the survival fraction to speed?
Test yourself
A clock on a spacecraft moving at 0.6$c$ records 8.0 s. The time interval measured from Earth is
$t = 8.0/0.80 = 10$ s.
A rod has a proper length of 2.0 m. Its length measured by an observer moving parallel to it at 0.866$c$ is
$\sqrt{1 - 0.866^2} = 0.50$, so $l = 1.0$ m.
Muons are detected at sea level in much larger numbers than expected without relativity. In the Earth's frame this is explained by
In Earth's frame the muons' clocks run slow; length contraction is the muon-frame explanation.
Which statement about proper time is correct?
Proper time is measured by a single clock present at both events, and is the shortest.
Label the light clock
A spacecraft flies from Earth to Mars at high speed. Sort each measurement.
A moving clock is measured to run . Lengths contract only to the direction of motion. The time measured by a clock present at both events is the time. In 1971, atomic flown on aircraft confirmed time dilation. Satellite navigation systems such as must correct for relativity.
Muons produced in the upper atmosphere, about 15 km above the ground, travel at 0.98$c$ towards the ground. Their mean lifetime at rest is 2.2 µs. (a) Calculate the mean distance travelled in one lifetime according to Newtonian physics. (b) Calculate the mean lifetime and distance measured by an observer on Earth. (c) Explain how an observer travelling with the muons accounts for the muons reaching the ground. (d) Explain why this provides evidence for special relativity.
(a) $v = 0.98 \times 3.00 \times 10^8 = 2.94 \times 10^8$ m/s; $d = vt_0 = (2.94 \times 10^8)(2.2 \times 10^{-6}) = 650$ m.
(b) $\sqrt{1 - 0.98^2} = 0.199$, so $t = \dfrac{2.2}{0.199} = 11$ µs and $d = (2.94 \times 10^8)(1.1 \times 10^{-5}) = 3.2$ km.
(c) In the muons' frame their lifetime is the proper time, 2.2 µs. However, the atmosphere is moving past them at 0.98$c$, so its thickness is length contracted by the factor 0.199: 15 km becomes about 3.0 km, which the muons can largely cross in their lifetime.
(d) Newtonian physics predicts almost no muons reach the ground. Detectors at sea level find many, in agreement with the numbers predicted by time dilation and length contraction. The two frames give different explanations but the same measured result, as required by the principle of relativity.
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