1E

Emission spectra and models of the atom

Photon energy and wavelength, how excited electrons produce line emission spectra, the flame test investigation and its limitations, and the Bohr and Schrödinger models of the atom compared.

When the fireworks go off over Sydney Harbour on New Year's Eve, the colours are chemistry. Strontium salts give the reds, barium the greens, copper the blues and sodium the golden yellows. Each metal's atoms, heated in the burst, give out light of exactly the same colours every time, and nobody has ever found a way to make strontium glow green. The reason those colours are fixed is the reason we know electrons sit in definite energy levels.

Light carries energy in packets

Visible light is part of the electromagnetic spectrum, with wavelengths from about 400 nm (violet) to 700 nm (red). Light behaves as a wave, with $c = f\lambda$, but it also arrives in packets of energy called photons. The energy of one photon is proportional to its frequency:

$$E = hf = \frac{hc}{\lambda}$$

where h = 6.626 × 10⁻³⁴ J s (Planck's constant), c = 3.00 × 10⁸ m s⁻¹ and λ is in metres. Shorter wavelength means higher energy: a violet photon carries almost twice the energy of a red one.

Energy of a sodium photon

Sodium's yellow light has a wavelength of 589 nm. Calculate the energy of one photon, and of one mole of photons.

$E = \dfrac{hc}{\lambda} = \dfrac{(6.626\times10^{-34})(3.00\times10^{8})}{589\times10^{-9}} = 3.37\times10^{-19}\text{ J}$

Per mole: $3.37\times10^{-19} \times 6.022\times10^{23} = 2.03\times10^{5}$ J mol⁻¹ = 203 kJ mol⁻¹, comparable to the energy of a chemical bond.

How atoms emit light

An atom with all its electrons in the lowest available levels is in its ground state. Heat or an electric discharge can give an electron enough energy to jump to a higher level: the atom is now in an excited state. Excited states are unstable. Within about a hundred-millionth of a second the electron falls back to a lower level and the energy difference is released as a single photon.

An electron absorbs energy, jumps to a higher level, and emits a photon as it falls back. The photon's energy equals the gap between the two levels.

Because the energy levels in an atom have fixed values, the gaps between them have fixed values too. So an element emits only certain wavelengths. Passing the light through a prism or diffraction grating spreads it into an emission line spectrum: a few bright coloured lines on a dark background. Every element's line spectrum is different, like a fingerprint. A hot solid such as a light bulb filament gives a continuous spectrum instead, containing every colour.

Continuous spectrum compared with the main visible lines of some elements. Some of the strontium lines are really narrow bands from molecules such as SrOH that form in a flame.

The reverse also happens. When white light passes through a cool gas, atoms absorb exactly the photons that match their energy gaps, leaving dark lines in a continuous spectrum: an absorption spectrum. In 1868 astronomers saw an unknown yellow line in the Sun's spectrum; the element responsible was named helium after the Greek word for the Sun, 27 years before it was found on Earth.

From an energy gap to a colour

In a hydrogen atom, the energy difference between levels n = 3 and n = 2 is 3.03 × 10⁻¹⁹ J. Calculate the wavelength of light emitted when an electron falls from n = 3 to n = 2, and state its colour.

$\lambda = \dfrac{hc}{E} = \dfrac{(6.626\times10^{-34})(3.00\times10^{8})}{3.03\times10^{-19}} = 6.56\times10^{-7}\text{ m}$

656 nm is red: the bright red line in the hydrogen spectrum.

Flame tests

A Bunsen flame is hot enough to excite the outer electrons of some metal ions, so each gives a characteristic colour. Not every metal does: magnesium, for example, has energy gaps that correspond to ultraviolet light, so a magnesium salt leaves the flame unchanged to your eye.

Metal ionFlame colour
Lithium, Li⁺crimson red
Sodium, Na⁺intense yellow-orange
Potassium, K⁺lilac (pale violet)
Calcium, Ca²⁺brick red (orange-red)
Strontium, Sr²⁺scarlet red
Barium, Ba²⁺pale (apple) green
Copper, Cu²⁺blue-green
InteractiveSpectrum detective
Try this
  • In Reference spectra, pick Na and leave the cursor on 589 nm. The photon energy reads 3.375 × 10⁻¹⁹ J (2.11 eV). Now move the cursor to 410 nm on hydrogen: why is the energy higher?
  • Open Mystery 1. The flame is yellow. Turn on the cobalt-blue glass and use the reference buttons to identify both metals.
  • Solve Mystery 2 and Mystery 3. Lithium and strontium are both red in a flame: how does the spectrum tell them apart?
  • Mystery 5 has three metals. What is the minimum number of lines you must match before you can be sure a metal is present?

The Bohr model

In 1913 Niels Bohr proposed that the electron in a hydrogen atom moves in circular orbits of fixed radius and fixed energy, labelled n = 1, 2, 3 ... An electron in an allowed orbit does not radiate energy. It absorbs or emits a photon only when it jumps between orbits, and the photon's energy equals the difference between them. Bohr calculated the energies of hydrogen's orbits and predicted the wavelengths of its spectral lines with remarkable accuracy.

Strengths: it explained why spectra are lines, gave the right wavelengths for hydrogen, and introduced quantised energy levels, which survive in all later models.

Limitations: it only worked for hydrogen and other one-electron ions; it could not explain the spectra of atoms with two or more electrons, why some lines are brighter than others, or why some lines split into closely spaced pairs; and it gave no reason why an orbiting electron should not radiate and spiral into the nucleus.

The Schrödinger model

In the 1920s Louis de Broglie suggested that electrons behave as waves, and in 1926 Erwin Schrödinger wrote an equation describing an electron as a standing wave around the nucleus. Its solutions are orbitals: three-dimensional regions in which there is a high probability of finding the electron. The model does not give the electron an exact path. Heisenberg's uncertainty principle says that is impossible anyway: you cannot know an electron's position and momentum precisely at the same time.

The solutions come out naturally in families that match the s, p, d and f subshells, with exactly the shapes and numbers of orbitals in lesson 1D. That is why the Schrödinger model, now called the quantum mechanical model, explains the spectra of all elements and the structure of the periodic table.

Bohr pictured definite orbits. Schrödinger's model gives a cloud of probability: denser where the electron is more likely to be.
Bohr (1913)Schrödinger (1926)
Electron described asa particle in a circular orbita wave; position given only as a probability
Energy levelsquantised shells n = 1, 2, 3quantised shells split into s, p, d, f subshells
Location of electronexact radiusorbital (region of high probability)
Explainshydrogen's line spectrumspectra of all atoms, the periodic table, bond shapes
Main weaknessfails for atoms with more than one electronmathematically complex; solved exactly only for hydrogen and approximated for others

Test yourself

  1. Which statement best explains why elements produce line spectra rather than continuous spectra?

  2. A photon has an energy of 4.85 × 10⁻¹⁹ J. Its wavelength is

  3. A main limitation of the Bohr model is that it

  4. A sample gives a yellow flame. Through cobalt-blue glass, a lilac flame is seen. The sample contains

  5. In the Schrödinger model, an orbital is

Label the emission diagram.

n = 1n = 2n = 3n = 4n = 5absorbsenergy (heat)falls back:emits a photonground state n = 1; excited states higherPhoton energy equals the gap:ΔE = E(high) − E(low) = hf = hc/λGaps are fixed for each element,so only certain wavelengths appear:a line spectrumhydrogen: 410, 434, 486, 656 nmbigger gap → higher energy → shorter λ

Which model does each statement describe?

An atom with all electrons in their lowest levels is in its state. When an electron falls to a lower level, a is emitted. The energy of the photon equals the between the two energy levels. Light of shorter carries more energy. The yellow flame of can hide other flame colours.

6 marks

A student performs flame tests on solutions of lithium chloride and strontium chloride. Both flames appear red. (a) Explain, in terms of electrons and energy levels, how the red light is produced. (b) Explain how the student could reliably distinguish the two metals. (c) Evaluate the flame test as a method of identifying metal ions.