Finding unknown angles
Using inverse sine, cosine and tangent to find an angle from two sides, rounding to the nearest degree or minute.
Inverse ratios
If $\tan\theta = \dfrac{5}{8}$, then $\theta = \tan^{-1}\left(\dfrac{5}{8}\right)$. The inverse button (often SHIFT then tan) turns a ratio back into an angle.
Find $\theta$ when the opposite side is $5$ and the adjacent side is $8$.
Find $\theta$ when the adjacent side is $7$ and the hypotenuse is $10$.
Opposite $5$, adjacent $8$. Find $\theta$ to the nearest degree.
$\tan^{-1}(5/8) \approx 32.0^\circ$.
Adjacent $7$, hypotenuse $10$. Find $\theta$ to 1 d.p.
$\cos^{-1}(0.7)$.
Opposite $4$, hypotenuse $9$. Find $\theta$ to 1 d.p.
$\sin^{-1}(4/9)$.
Opposite and adjacent sides are both $6$. Find $\theta$.
$\tan\theta = 1$.
Opposite $4$, hypotenuse $8$. Find $\theta$.
$\sin\theta = 0.5$.
Sides $3, 4, 5$. Find the angle opposite the side of length $3$, to 1 d.p.
$\tan^{-1}(3/4)$.
Adjacent $5$, hypotenuse $10$. Find $\theta$.
$\cos\theta = 0.5$.
Write $45.57^\circ$ in degrees and minutes. How many minutes (nearest)?
$0.57 \times 60 = 34.2$.
New numbers every time. Keep going until you get five in a row.
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