Graphing straight lines
Sketching lines using the x- and y-intercepts, lines through the origin, and horizontal and vertical lines.
The intercept method
Sketch $3x + 2y = 12$.
$x = 0$: $2y = 12$, so $y = 6$.
$y = 0$: $3x = 12$, so $x = 4$.
Join $(0, 6)$ and $(4, 0)$.
Change a, b and c and watch the intercepts move.
Lines with one intercept
- $y = mx$ passes through the origin; find a second point by substituting, e.g. $x = 1$.
- $y = k$ is horizontal; $x = h$ is vertical.
$y$-intercept
Set $x = 0$.
$y = -2$
Horizontal line
$y = 4x$
Through the origin
For $3x + 2y = 12$, give the $x$-intercept then the $y$-intercept.
$x = 4$, $y = 6$.
For $2x - 5y = 10$, give the $x$-intercept then the $y$-intercept.
$2x = 10$; $-5y = 10$.
The line $x = -2$ is:
All points have $x = -2$.
Which line passes through the origin?
No constant term.
Find the $y$-intercept of $y = 3 - 2x$.
Set $x = 0$.
Find the $x$-intercept of $y = 3 - 2x$.
$2x = 3$.
For $x + 4y = 8$, find the $x$-intercept.
Set $y = 0$.
Where do $y = 4$ and $x = -1$ meet?
A horizontal and a vertical line meet at one point.
New numbers every time. Keep going until you get five in a row.
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