5A

Circumference, arcs and sector perimeters

Circumference of a circle, arc length as a fraction of the circumference, and perimeters of sectors, semicircles and composite shapes.

Circumference and arcs

Circumference and arc length
$$C = 2\pi r = \pi d \qquad \ell = \frac{\theta}{360} \times 2\pi r$$
Arc length grows with radius and angle

The line shows arc length against radius for the chosen angle.

Example 1●●

Find the perimeter of a sector with radius $6$ cm and angle $60^\circ$.

Arc $= \dfrac{60}{360} \times 2\pi \times 6 = 2\pi \approx 6.28$ cm
Perimeter $= 6 + 6 + 6.28 = 18.28$ cm
Flashcards
Circumference
$2\pi r$ or $\pi d$
Arc length
$\dfrac{\theta}{360} \times 2\pi r$
Semicircle perimeter
$\pi r + 2r$
Practice
  1. Perimeter of a sector, radius $6$ cm, angle $60^\circ$ (2 d.p.)?

  2. Circumference of a circle with radius $5$ (2 d.p.)?

  3. Perimeter of a semicircle with diameter $10$ (2 d.p.)?

  4. The exact arc length for radius $6$, angle $60^\circ$ is:

  5. A circle has circumference $20\pi$. Find its radius.

  6. Arc length of a quarter circle of radius $14$ (2 d.p.)?

  7. An arc of a circle with radius $8$ has length $4\pi$. Find the angle.

  8. How far does the tip of a $1$ m clock hand travel in one revolution (2 d.p.)?

More questions

New numbers every time. Keep going until you get five in a row.

Formula sheet