Solving problems with simultaneous equations
Writing a pair of equations from a worded problem, solving, and answering in context.
Method
Adult tickets cost $\$15$ and child tickets $\$8$. A group bought $20$ tickets for $\$230$. How many adults?
Three pens and two pencils cost $\$8.50$. One pen and two pencils cost $\$4.50$. Find the cost of a pen.
$\$15$ adult and $\$8$ child tickets; $20$ tickets cost $\$230$. How many adults?
$7a = 70$.
$3$ pens and $2$ pencils cost $\$8.50$; $1$ pen and $2$ pencils cost $\$4.50$. Cost of a pen?
Subtract: $2p = 4$.
Two numbers add to $87$ and differ by $29$. Enter the larger, then the smaller.
$2x = 116$.
Using the pens question, what does a pencil cost in dollars?
$2 + 2q = 4.5$.
A farm has chickens and cows: $30$ heads and $84$ legs. How many cows?
$c + k = 30$, $2c + 4k = 84$, so $2k = 24$.
Twice a number plus another number is $40$; their difference (first minus second) is $2$. Find the first number.
$2x + y = 40$, $x - y = 2$: add to get $3x = 42$.
A rectangle's length is $6$ cm more than its width and its perimeter is $60$ cm. Length?
$l = w + 6$, $2l + 2w = 60$, so $w = 12$.
Plan A costs $\$20 + \$0.50$ per GB, plan B costs $\$40$ flat. At how many GB do they cost the same?
$20 + 0.5g = 40$.
New numbers every time. Keep going until you get five in a row.
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