Linear equations and ax² = c
Solving linear equations with brackets, pronumerals on both sides and algebraic fractions, and solving quadratic equations of the form ax² = c.
Harder linear equations
Solve $5(x - 2) = 3(x + 4)$.
Solve $\dfrac{2x - 1}{3} = \dfrac{x + 4}{2}$.
Solve $\dfrac{x}{3} + \dfrac{x}{4} = 7$.
Equations $ax^2 = c$
Solve $3x^2 = 48$.
Solve $5(x - 2) = 3(x + 4)$.
$2x = 22$.
Solve $\dfrac{2x - 1}{3} = \dfrac{x + 4}{2}$.
$4x - 2 = 3x + 12$.
Solve $\dfrac{x}{3} + \dfrac{x}{4} = 7$.
$7x = 84$.
Solve $3x^2 = 48$. Enter both solutions.
$x^2 = 16$.
Solve $2(3x + 1) = 4x - 2$.
$6x + 2 = 4x - 2$, so $2x = -4$.
Solve $\dfrac{x + 3}{4} = \dfrac{x - 1}{2}$.
$x + 3 = 2(x - 1)$, so $x = 5$.
Solve $2x^2 - 5 = 13$.
$x^2 = 9$.
Solve $\dfrac{x}{2} - \dfrac{x}{5} = 3$.
$5x - 2x = 30$.
New numbers every time. Keep going until you get five in a row.
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