6B

Zero and negative indices

The zero index, negative indices as reciprocals, and simplifying expressions to positive indices.

The zero index

$\dfrac{a^3}{a^3} = a^{3-3} = a^0$, but anything divided by itself is $1$. So $a^0 = 1$ for any $a \ne 0$.

Negative indices

Negative index
$$a^{-n} = \frac{1}{a^n}$$
Powers of 2 below zero

Each step left halves the value: 2⁰ = 1, 2⁻¹ = ½, 2⁻² = ¼, ...

Example 1●●

Evaluate $2^{-3}$ and write $5x^{-2}$ with a positive index.

$2^{-3} = \dfrac{1}{8}$
$5x^{-2} = \dfrac{5}{x^2}$ (the $5$ has no negative index)
Flashcards
$7^0$
$1$
$4^{-1}$
$\tfrac{1}{4}$
$dfrac{1}{x^3}$
$x^{-3}$
Practice
  1. Evaluate $2^{-3}$.

  2. Evaluate $(3x)^0$.

  3. Evaluate $3x^0$.

  4. Evaluate $10^{-2}$ as a decimal.

  5. Evaluate $4^{-1}$.

  6. Write $5x^{-2}$ with a positive index.

  7. Simplify $x^2 \div x^5$, leaving a negative index.

  8. Evaluate $\left(\dfrac{1}{3}\right)^{-2}$.

More questions

New numbers every time. Keep going until you get five in a row.

Formula sheet