Applying similar triangles
Proving triangles similar, nested triangles with a parallel side, and solving shadow and height problems.
Nested triangles
If $DE \parallel BC$ in $\triangle ABC$, then $\triangle ADE \sim \triangle ABC$ (AAA: $\angle A$ is common, and corresponding angles on parallel lines are equal).
In $\triangle ABC$, $D$ is on $AB$ and $E$ on $AC$ with $DE \parallel BC$. $AD = 4$, $DB = 6$ and $DE = 5$. Find $BC$.
Shadows and heights
A $1.8$ m person casts a $2.4$ m shadow. At the same time a tree casts a $16$ m shadow. How tall is the tree?
$DE \parallel BC$, $AD = 4$, $DB = 6$, $DE = 5$. Find $BC$.
$k = 2.5$.
$1.8$ m person, $2.4$ m shadow. Tree shadow $16$ m. Tree height?
$16 \times 0.75$.
$DE \parallel BC$, $AD = 3$, $AB = 9$, $BC = 18$. Find $DE$.
$k = 3$, $18 \div 3$.
Why are $\triangle ADE$ and $\triangle ABC$ similar when $DE \parallel BC$?
All three angles match.
$DE \parallel BC$, $AD = 2$, $DE = 3$, $BC = 15$. Find $AB$.
$k = 5$.
Find $DB$ in the previous question.
$10 - 2$.
A $3$ m pole casts a $4$ m shadow. A building casts a $60$ m shadow. Building height?
$60 \times 0.75$.
A $2$ m stick casts a shadow of $x$ m while a $15$ m flagpole casts an $18$ m shadow. Find $x$.
$\tfrac{x}{2} = \tfrac{18}{15}$.
New numbers every time. Keep going until you get five in a row.
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