Arcs and sectors of circles
Arc length ℓ = rθ, sector area A = ½r²θ, major and minor arcs and sectors, and the area of a segment.
Arc length and sector area
The sector is between the two blue radii, measured anticlockwise from the positive x-axis.
Set $\theta = \pi$. Check that the sector area is half the circle.
A sector has radius $6$ and angle $\dfrac{\pi}{3}$. Find the arc length, the sector area and the area of the minor segment.
Major and minor arcs
Two radii split a circle into a minor sector (angle $\theta < \pi$) and a major sector (angle $2\pi - \theta$). Use the matching angle in the formulas.
Find the arc length when $r = 5$ and $\theta = 2$.
$5 \times 2$.
Find the sector area when $r = 4$ and $\theta = 1.5$.
$\tfrac12 \times 16 \times 1.5$.
Find the exact arc length when $r = 6$ and $\theta = \dfrac{\pi}{3}$ (type like 2pi).
$6 \times \dfrac{\pi}{3}$.
Find the area of the minor segment when $r = 6$ and $\theta = \dfrac{\pi}{3}$, to 2 decimal places.
$6\pi - 9\sqrt3 \approx 3.26$.
An arc of length $12$ cm is on a circle of radius $8$ cm. Find the angle in radians.
$\theta = \dfrac{\ell}{r}$.
Two radii of a circle of radius $3$ make a right angle. Find the length of the major arc, to 2 decimal places.
Major angle $2\pi - \dfrac{\pi}{2} = \dfrac{3\pi}{2}$, so $\ell = \dfrac{9\pi}{2} \approx 14.14$.
Find the perimeter of a sector with $r = 5$ and $\theta = 1.2$.
Two radii plus the arc: $10 + 6$.
If the angle of a sector is doubled (same radius), its area:
Area is proportional to $\theta$.
A sector of radius $4$ has area $24$. Find its angle.
$\tfrac12 \times 16 \times \theta = 24$.
New numbers every time. Keep going until you get five in a row.
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