Expanding brackets
Like terms, the distributive law, expanding binomial products and the three special expansions: perfect squares and the difference of squares.
Like terms
have exactly the same pronumerals with the same powers. You can add and subtract like terms, but not unlike ones: $3x^2 + 5x^2 = 8x^2$, but $3x^2 + 5x$ cannot be simplified.
The distributive law
Every expansion comes from one law: multiply each term inside the bracket by the term outside.
Expand and simplify $3(2x - 5) - 2(x - 4)$.
Expand $(2x + 3)(x - 4)$.
The three special expansions
Three products appear so often that you should recognise them instantly, both forwards (expanding) and backwards (factoring).
Expand $(3a - 2b)^2$ and $(5x + 1)(5x - 1)$.
Orange: the product of brackets. Dashed blue: your expanded answer. If your expansion is right, the two graphs are identical for every x.
Set $p$ and $q$, expand $(x + p)(x + q)$ in your head, then set "your b" and "your c" to match. The graphs tell you if you are right.
$(x - 5)^2 =$
$A^2 - 2AB + B^2$ with $A = x$, $B = 5$.
$(2x + 7)(2x - 7) =$
Difference of squares: $(2x)^2 - 7^2$.
Expand and simplify $(x + 2)(3x - 1) - 3x^2$. What is the coefficient of $x$?
$(x + 2)(3x - 1) = 3x^2 - x + 6x - 2 = 3x^2 + 5x - 2$. Subtracting $3x^2$ leaves $5x - 2$, so the coefficient is $5$.
$-3(2x - 5) =$
The $-3$ multiplies both terms: $-3 \times 2x = -6x$ and $-3 \times -5 = +15$.
Simplify $4a^2b - 7a^2b + a^2b$. Enter the coefficient of $a^2b$.
These are like terms: $4 - 7 + 1 = -2$.
$(3x - 1)^2 =$
$A^2 - 2AB + B^2$ with $A = 3x$, $B = 1$.
Expand $(2x - 3)(x + 5)$. What is the coefficient of $x$?
$2x^2 + 10x - 3x - 15 = 2x^2 + 7x - 15$.
Which pair are like terms?
$ab$ and $ba$ are the same product, so $4ab$ and $-ba$ are like terms.
New numbers every time. Keep going until you get five in a row.
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