10C

A rule for differentiating powers of x

The power rule, differentiating sums and multiples, expanding products first, and finding tangents and normals to a curve.

The power rule

Power rule
$$\frac{d}{dx}\,x^n = nx^{n-1}$$

Constant multiples and sums differentiate term by term: if $f(x) = ag(x) + bh(x)$, then $f'(x) = ag'(x) + bh'(x)$.

Example 1●

Differentiate $f(x) = 4x^3 - 5x^2 + 7x - 2$.

$f'(x) = 12x^2 - 10x + 7$
Example 2: expand first●●

Differentiate $y = (2x + 1)(x - 3)$.

$y = 2x^2 - 5x - 3$
$\dfrac{dy}{dx} = 4x - 5$

Tangents and normals

Example 3●●●

Find the tangent and normal to $y = x^2 - 4x + 5$ at $x = 3$.

$y = 9 - 12 + 5 = 2$, so the point is $(3, 2)$.
$\dfrac{dy}{dx} = 2x - 4 = 2$ at $x = 3$.
Tangent: $y - 2 = 2(x - 3)$, so $y = 2x - 4$.
Normal: gradient $-\tfrac12$, $y - 2 = -\tfrac12(x - 3)$, so $x + 2y - 7 = 0$.
Tangent and normal

Blue dashed: the tangent. Pink dashed: the normal, at right angles to it.

Try this

At which point is the normal vertical?

Flashcards
$rac{d}{dx},x^n$
$nx^{n-1}$
Tangent gradient
$f'(x_1)$
Normal gradient
$-\dfrac{1}{f'(x_1)}$
Practice
  1. $\dfrac{d}{dx}\,x^7 = $

  2. For $f(x) = 4x^3 - 5x^2 + 7x - 2$, find $f'(1)$.

  3. The derivative of $(2x + 1)(x - 3)$ is:

  4. Find the gradient of the tangent to $y = x^2 - 4x + 5$ at $x = 3$.

  5. The tangent to $y = x^2 - 4x + 5$ at $(3, 2)$ is:

  6. The normal at that point has gradient:

  7. Find $x$ where the tangent to $y = x^2 - 6x$ is horizontal.

  8. For $f(x) = \dfrac{x^3 + 2x^2}{x}$, find $f'(2)$.

  9. Find both $x$-values where $y = x^3 - 12x$ has gradient $0$.

More questions

New numbers every time. Keep going until you get five in a row.

Formula sheet