Factor any expression using the four methods in order: highest common factor, difference of squares, quadratic trinomials (monic and non-monic) and grouping.
The factoring checklist
Factoring is expanding in reverse. With so many methods it helps to try them in a fixed order every time:
Example 1: HCF then difference of squares●
Factor $3x^3 - 12x$.
$= 3x(x^2 - 4)$
3 and x divide every term.
$= 3x(x - 2)(x + 2)$
x² − 4 = x² − 2² is a difference of squares.
Monic quadratics: $x^2 + bx + c$
Find two numbers that multiply to $c$ and add to $b$. Then $x^2 + bx + c = (x + m)(x + n)$.
Example 2●
Factor $x^2 - x - 12$.
Numbers: $3$ and $-4$.
Pairs that multiply to −12: (1, −12), (2, −6), (3, −4), (−3, 4)... Only 3 and −4 add to −1.
$x^2 - x - 12 = (x + 3)(x - 4)$
Non-monic quadratics: $ax^2 + bx + c$
When $a \ne 1$, find two numbers that multiply to $ac$ and add to $b$. Use them to split the middle term, then group.
Example 3●●
Factor $6x^2 + x - 2$.
We need two numbers multiplying to $-12$ and adding to $1$: they are $4$ and $-3$.
a × c = 6 × (−2) = −12.
$6x^2 + 4x - 3x - 2$
Split the middle term x into 4x − 3x.
$= 2x(3x + 2) - 1(3x + 2)$
Take a common factor from each pair. The brackets must match.
$= (3x + 2)(2x - 1)$
Grouping in pairs
Example 4●●
Factor $x^3 + 2x^2 - 9x - 18$.
$= x^2(x + 2) - 9(x + 2)$
Take a common factor out of the first pair and out of the second pair.
$= (x + 2)(x^2 - 9)$
$= (x + 2)(x - 3)(x + 3)$
Check every factor: x² − 9 is a difference of squares.
Flashcards
First step in any factoring
Take out the highest common factor.
Monic x² + bx + c
Two numbers that multiply to $c$ and add to $b$.
Non-monic ax² + bx + c
Two numbers that multiply to $ac$ and add to $b$, then split and group.
Four terms
Try grouping in pairs.
A² − B²
$(A - B)(A + B)$
Practice
Factor $x^2 - 49$.
A difference of squares: $x^2 - 7^2$.
Factor $2x^2 + 7x + 3$.
Numbers multiplying to $6$ and adding to $7$ are $6$ and $1$: $2x^2 + 6x + x + 3 = 2x(x + 3) + 1(x + 3)$.
Which is the first step to factor $5x^2 - 20$?
Always take out the HCF first: $5(x^2 - 4) = 5(x - 2)(x + 2)$.