Applications of exponential and log functions
Exponential growth and decay models, doubling time and half-life, rearranging formulas between index and log form, and log scales such as pH.
Growth and decay
$Q_0$ is the starting amount. If $a > 1$ the quantity grows; if $0 < a < 1$ it decays. A quantity that doubles every $T$ years is $Q = Q_0 \times 2^{\frac{t}{T}}$, and one that halves every $T$ years is $Q = Q_0 \times \left(\tfrac12\right)^{\frac{t}{T}}$.
A population starting at Q₀ million that doubles every T years.
How long does it take to triple when $T = 30$? Check Example 1.
A population of $3$ million doubles every $30$ years. When will it reach $9$ million?
Carbon-14 has a half-life of $5730$ years. What fraction of the original remains after $2000$ years?
Rearranging formulas
Rewrite $Q = 5 \times 10^{\frac{t}{2}}$ with $t$ as the subject.
Log scales
Some measurements use logs to squeeze huge ranges into small numbers. Acidity uses $\text{pH} = -\log_{10} [\text{H}^+]$, so each drop of $1$ in pH means $10$ times the hydrogen ion concentration. The Richter scale and decibels work the same way.
$Q = 5 \times 10^{\frac{t}{2}}$. Find $Q$ when $t = 4$.
$5 \times 10^2 = 500$.
For the same formula, find $t$ when $Q = 2000$, correct to 3 decimal places.
$10^{\frac{t}{2}} = 400$, so $t = 2\log_{10} 400 \approx 5.204$.
A population of $3$ million doubles every $30$ years. Find the population, in millions, after $90$ years.
$3 \times 2^3 = 24$.
A substance has a half-life of $8$ days. What fraction remains after $24$ days?
Three half-lives: $\left(\tfrac12\right)^3 = \tfrac18$.
An investment grows by $5\%$ per year. After how many whole years will it first have doubled?
$1.05^n \ge 2$ gives $n \ge \dfrac{\log 2}{\log 1.05} \approx 14.2$, so $15$ years.
How many times more acidic is a solution with pH $4$ than one with pH $6$?
Two pH units is $10^2 = 100$.
A chip's transistor count doubles every $2$ years. By what factor does it grow in $20$ years?
$2^{10} = 1024$.
A quantity is multiplied by $0.9$ each year. After how many whole years is it first below half its starting value?
$0.9^n < 0.5$ gives $n > \dfrac{\log 0.5}{\log 0.9} \approx 6.58$, so $7$ years.
Rewrite $t = 20\log_2 (2Q)$ with $Q$ as the subject.
$2Q = 2^{\frac{t}{20}}$, so $Q = \tfrac12 \times 2^{\frac{t}{20}}$.
New numbers every time. Keep going until you get five in a row.
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