Graphs with asymptotes: exponentials and hyperbolas
Sketch exponential graphs and rectangular hyperbolas, find their asymptotes, and use limit notation to describe what happens at the edges.
What is an asymptote?
An is a line the graph approaches more and more closely but never reaches. Draw asymptotes as dashed lines and label their equations.
We describe this approach with limit notation. "As $x \to \infty$, $y \to 0$" means: as $x$ gets larger and larger, $y$ gets closer and closer to $0$.
Exponential functions
An exponential function has the variable in the index: $y = a^x$ with $a > 0$ and $a \ne 1$.
- It always passes through $(0, 1)$, because $a^0 = 1$.
- It is always positive, so its range is $y > 0$.
- The $x$-axis ($y = 0$) is a horizontal asymptote.
- If $a > 1$ it increases (growth). If $0 < a < 1$ it decreases (decay).
- Which point stays fixed as you change $a$?
- Compare $a = 2$ with $a = 0.5$. How are the two graphs related?
The rectangular hyperbola
The graph of $y = \dfrac{k}{x}$ is a rectangular hyperbola. It has two separate branches, and both axes are asymptotes:
- Vertical asymptote $x = 0$, because we cannot divide by zero.
- Horizontal asymptote $y = 0$, because $\dfrac{k}{x} \to 0$ as $x \to \pm\infty$.
If $k > 0$ the branches are in the 1st and 3rd quadrants; if $k < 0$ they are in the 2nd and 4th.
The dashed pink lines are the asymptotes. They move with the graph.
- Find where this hyperbola crosses the $y$-axis by hovering. Check it by substituting $x = 0$.
- Set $k$ negative. Which quadrants (relative to the asymptotes) do the branches move to?
Sketch $y = \dfrac{3}{x - 2} + 1$, showing asymptotes and intercepts.
Sketch $y = 2^x - 4$ and state its range.
The horizontal asymptote of $y = 3^x + 2$ is:
$3^x \to 0$ as $x \to -\infty$, so $y \to 2$.
$y = \dfrac{-2}{x}$ has branches in which quadrants?
$k = -2 < 0$: for positive $x$, $y$ is negative (4th quadrant), and for negative $x$, $y$ is positive (2nd quadrant).
$y = \dfrac{1}{x + 3}$ has a vertical asymptote $x = \ ?$
The denominator is zero when $x = -3$.
Every graph $y = a^x$ (with $a > 0$, $a \ne 1$) passes through:
$a^0 = 1$ for every allowed $a$.
The range of $y = 2^{-x}$ is:
An exponential is always positive and never reaches $0$.
Find the $y$-intercept of $y = 3^x - 5$.
$3^0 - 5 = 1 - 5 = -4$.
As $x \to \infty$, $\dfrac{4}{x} \to$
Dividing $4$ by larger and larger numbers gives values closer and closer to $0$.
Find the $x$-intercept of $y = \dfrac{2}{x + 1} - 1$.
$\dfrac{2}{x + 1} = 1$, so $x + 1 = 2$ and $x = 1$.
New numbers every time. Keep going until you get five in a row.
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