Venn diagrams and the addition theorem
Mutually exclusive events, the addition theorem P(A ∪ B) = P(A) + P(B) − P(A ∩ B), and using Venn diagrams for "or" questions.
The addition theorem
This is the counting rule divided by $|S|$. Events that cannot happen together are mutually exclusive: $P(A \cap B) = 0$, so $P(A \cup B) = P(A) + P(B)$.
A card is drawn. Find $P(\text{heart or king})$.
$P(A \cup B) = 0.8$, $P(A) = 0.5$ and $P(B) = 0.6$. Find $P(A \cap B)$ and $P(\text{neither})$.
Find $P(\text{heart or king})$ for one card.
$\dfrac{16}{52}$.
$P(A) = 0.5$, $P(B) = 0.3$, $P(A \cap B) = 0.1$. Find $P(A \cup B)$.
$0.5 + 0.3 - 0.1$.
$A$ and $B$ are mutually exclusive when:
They cannot happen together.
A die is rolled. Find $P(\text{even or greater than } 4)$.
$\{2, 4, 5, 6\}$: four of six.
$A$ and $B$ are mutually exclusive with $P(A) = 0.4$ and $P(B) = 0.35$. Find $P(A \cup B)$.
Just add.
$P(A \cup B) = 0.8$, $P(A) = 0.5$, $P(B) = 0.6$. Find $P(A \cap B)$.
$0.5 + 0.6 - 0.8$.
For the same events, find $P(\text{neither})$.
$1 - 0.8$.
Which pair is mutually exclusive when one card is drawn?
A card cannot be in two suits.
A number is chosen from $1$ to $20$. Find $P(\text{multiple of 4 or multiple of 5})$.
$5 + 4 - 1 = 8$ numbers ($20$ is in both), so $\dfrac{8}{20}$.
New numbers every time. Keep going until you get five in a row.
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