Equations involving logarithms and indices
The change-of-base formula, solving index equations by matching bases or taking logs, equations that reduce to quadratics, log equations, and exponential inequations.
The change-of-base formula
Use it with $b = 10$ (or $b = e$) to evaluate any log on a calculator: $\log_3 20 = \dfrac{\log_{10} 20}{\log_{10} 3} \approx 2.727$.
Solving index equations
Solve $3^{x+1} = 27^x$.
Solve $2^x = 10$, correct to 3 decimal places.
The solution is the x-coordinate where the dashed line meets the curve.
Why is there never a solution when $k \le 0$?
Equations reducible to quadratics
Solve $4^x - 3 \times 2^x - 4 = 0$.
Log equations
Solve $\log_2 x + \log_2 (x - 2) = 3$.
Inequations
Find the smallest whole number $n$ with $0.8^n < 0.1$.
Find $\log_3 20$, correct to 3 decimal places.
$\dfrac{\log_{10} 20}{\log_{10} 3} \approx 2.727$.
Solve $2^x = 10$, correct to 3 decimal places.
$x = \log_2 10 \approx 3.322$.
Solve $3^{x+1} = 27^x$.
$x + 1 = 3x$.
Solve $4^x - 3 \times 2^x - 4 = 0$.
$2^x = 4$ (the other root $2^x = -1$ is impossible).
The solution of $2^x > 50$ is:
$y = 2^x$ is increasing, so $x > \log_2 50$.
Find the smallest whole number $n$ with $0.8^n < 0.1$.
$n > 10.3$, so $n = 11$.
Solve $\log_2 x + \log_2 (x - 2) = 3$.
$x(x - 2) = 8$ gives $x = 4$ or $-2$, and $-2$ is rejected.
Solve $5^{2x} = 3^{x+1}$, correct to 3 decimal places.
Take logs: $2x\log 5 = (x + 1)\log 3$, so $x(2\log 5 - \log 3) = \log 3$ and $x = \dfrac{\log 3}{2\log 5 - \log 3} \approx 0.518$.
Solve $\log_x 81 = 4$.
$x^4 = 81$ with $x > 0$.
New numbers every time. Keep going until you get five in a row.
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