Equations of lines
Horizontal and vertical lines, gradient–intercept form y = mx + b, and general form ax + by + c = 0, and converting between them.
Horizontal and vertical lines
Every point on a horizontal line has the same $y$-coordinate, so its equation is $y = k$. Every point on a vertical line has the same $x$-coordinate: $x = h$. The $x$-axis is $y = 0$ and the $y$-axis is $x = 0$.
Two standard forms
Gradient–intercept form
$$y = mx + b$$Gradient $m$, $y$-intercept $b$.
General form
$$ax + by + c = 0$$Integer coefficients, usually with $a > 0$. Every line, including vertical ones, can be written this way.
Change a, b and c in ax + by + c = 0 and read the gradient and intercepts.
Which coefficient must be zero for a horizontal line? For a vertical line?
Write $y = -\tfrac23 x + 4$ in general form.
Find the gradient and both intercepts of $4x - 5y + 20 = 0$.
The vertical line through $(-3, 4)$ is:
Every point has $x = -3$.
Find the gradient of $3x + 2y - 7 = 0$.
$y = -\tfrac32 x + \tfrac72$.
Find the $y$-intercept of $x - 2y + 8 = 0$.
$x = 0$: $-2y + 8 = 0$, so $y = 4$.
$y = \tfrac12 x - 3$ in general form is:
$2y = x - 6$, so $x - 2y - 6 = 0$.
Which line is parallel to $y = 3x - 1$?
$y = 3x + 4$ has gradient $3$.
Find the $x$-intercept of $2x - 3y + 12 = 0$.
$y = 0$: $2x = -12$.
The $x$-axis has equation:
Every point on the $x$-axis has $y = 0$.
For which $k$ does $kx + y - 3 = 0$ have gradient $-5$?
$y = -kx + 3$, so $-k = -5$.
New numbers every time. Keep going until you get five in a row.
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