The remainder and factor theorems
The remainder theorem and the factor theorem with proofs, finding integer zeroes from factors of the constant term, and factoring a polynomial fully.
The remainder theorem
Find the remainder when $P(x) = x^3 - 4x^2 + 2x + 5$ is divided by $x + 1$.
The factor theorem
This is the remainder theorem with remainder zero. It turns "is this a factor?" into a one-line calculation.
The remainder on dividing by x − a is the height of the graph at x = a. Drag A onto each x-intercept.
Drag $A$ to each of the three intercepts. What are the three linear factors?
Factoring a polynomial
Factor $P(x) = x^3 - 2x^2 - 5x + 6$ fully.
$x - 2$ is a factor of $P(x) = x^3 + kx^2 - 4x + 12$. Find $k$, then the other zeroes.
Find the remainder when $x^3 - 4x^2 + 2x + 5$ is divided by $x + 1$.
$P(-1) = -2$.
$(x - 3)$ is a factor of $P(x)$ exactly when:
The factor theorem.
Find the remainder when $x^3 - 2x^2 - 5x + 6$ is divided by $x - 3$.
$27 - 18 - 15 + 6 = 0$, so $x - 3$ is a factor.
$x - 2$ is a factor of $x^3 + kx^2 - 4x + 12$. Find $k$.
$8 + 4k - 8 + 12 = 0$.
Which could be an integer zero of $x^3 + 4x^2 - x - 10$?
Integer zeroes divide $10$, so only $\pm 1, \pm 2, \pm 5, \pm 10$ are possible. Check: $-8 + 16 + 2 - 10 = 0$.
Factor $x^3 - 2x^2 - 5x + 6$.
See Example 2.
Find the remainder when $4x^2 + 2x - 3$ is divided by $2x - 1$.
Substitute $x = \tfrac12$, which makes $2x - 1$ zero: $4 \times \tfrac14 + 2 \times \tfrac12 - 3 = -1$.
When $P(x)$ is divided by $x - 4$ the remainder is $5$. Find $P(4)$.
The remainder theorem.
The proof of the remainder theorem starts from:
Then substitute $x = a$.
New numbers every time. Keep going until you get five in a row.
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