Pascal’s triangle
Expanding (1 + x)^n, building Pascal's triangle with the addition property, its symmetry, and using a row to expand binomials such as (2 + x)^3 and (1 − 2x)^4.
The triangle
Expand $(1 + x)^n$ for $n = 0, 1, 2, \ldots$ and write down only the coefficients. Each row starts and ends with $1$.
| $n = 0$ | 1 |
| $n = 1$ | 1 1 |
| $n = 2$ | 1 2 1 |
| $n = 3$ | 1 3 3 1 |
| $n = 4$ | 1 4 6 4 1 |
| $n = 5$ | 1 5 10 10 5 1 |
| $n = 6$ | 1 6 15 20 15 6 1 |
Each row is also symmetric: it reads the same backwards. Row $n$ has $n + 1$ entries, and we count positions from $0$.
Using a row to expand
Expand $(1 + x)^4$.
Expand $(2 + x)^3$.
Expand $(1 - 2x)^4$.
Find the middle entry of row $6$ of Pascal's triangle.
$1, 6, 15, 20, 15, 6, 1$.
Find the coefficient of $x^2$ in $(1 + x)^5$.
Row $5$: $1, 5, 10, \ldots$
How many entries are there in row $6$?
Row $n$ has $n + 1$ entries.
Row $7$ of Pascal's triangle is:
Add neighbours in row $6$: $1 + 6$, $6 + 15$, $15 + 20$, and so on.
Find the coefficient of $x$ in $(2 + x)^3$.
$3 \times 2^2$.
Find the coefficient of $x^3$ in $(1 - 2x)^4$.
$4 \times (-2)^3$.
Find the coefficient of $x^2$ in $(1 - 2x)^4$.
$6 \times (-2)^2$.
$(1 + x)^3 = $
Row $3$.
Why is each row of Pascal's triangle symmetric?
Reading the coefficients from either end gives the same expansion.
New numbers every time. Keep going until you get five in a row.
Coaching Centre