Sums and products of zeroes
Formulae for the sum and product of zeroes of quadratics, cubics and quartics, the general pattern, and forming identities such as the sum of squares of the zeroes.
The formulae
Expand $a(x - \alpha)(x - \beta)(x - \gamma)$ and compare its coefficients with $ax^3 + bx^2 + cx + d$. The coefficients turn out to be built from the zeroes.
Quadratic $ax^2 + bx + c$
$$\alpha + \beta = -\frac{b}{a}, \qquad \alpha\beta = \frac{c}{a}$$
Cubic $ax^3 + bx^2 + cx + d$
$$\sum\alpha = -\frac{b}{a}, \quad \sum\alpha\beta = \frac{c}{a}, \quad \alpha\beta\gamma = -\frac{d}{a}$$
Here $\sum\alpha\beta$ means the sum of the products in pairs, $\alpha\beta + \beta\gamma + \gamma\alpha$.
Forming identities
The roots of $x^3 - 2x^2 + 3x + 5 = 0$ are $\alpha, \beta, \gamma$. Find $\alpha^2 + \beta^2 + \gamma^2$ and $\dfrac1\alpha + \dfrac1\beta + \dfrac1\gamma$.
Using extra information to factor
The roots of $x^3 - 6x^2 + 11x - 6 = 0$ form an arithmetic sequence. Solve the equation.
One root of $x^3 + px^2 - 4x - 12 = 0$ is the negative of another. Find $p$ and solve the equation.
The roots of $x^2 - 5x + 3 = 0$ are $\alpha$ and $\beta$. Find $\alpha + \beta$.
$-\dfrac{-5}{1}$.
The roots of $2x^3 - 4x^2 + x - 7 = 0$ are $\alpha, \beta, \gamma$. Find $\alpha + \beta + \gamma$.
$-\dfrac{-4}{2} = 2$.
For $2x^3 - 4x^2 + x - 7 = 0$, find $\alpha\beta\gamma$.
$-\dfrac{-7}{2} = \dfrac72$.
For $x^3 - 2x^2 + 3x + 5 = 0$, find $\alpha^2 + \beta^2 + \gamma^2$.
$2^2 - 2(3)$.
For $x^3 - 2x^2 + 3x + 5 = 0$, find $\dfrac1\alpha + \dfrac1\beta + \dfrac1\gamma$.
$\dfrac{3}{-5}$.
For the quartic $ax^4 + bx^3 + cx^2 + dx + e$, the product of the zeroes is:
Signs alternate $-, +, -, +$, and the product is the fourth.
The roots of $x^3 - 6x^2 + 11x - 6 = 0$ form an arithmetic sequence. Find the middle root.
$3a = 6$.
$\alpha^2 + \beta^2 + \gamma^2$ equals:
Expand $(\alpha + \beta + \gamma)^2$.
The roots of $x^3 + kx^2 + 2x - 8 = 0$ add to $6$. Find $k$.
$-k = 6$.
For a monic cubic with roots $1, 2, 3$, the constant term is:
$\alpha\beta\gamma = -d$, so $d = -6$.
New numbers every time. Keep going until you get five in a row.
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