Graphs of polynomial functions
Sketch polynomials from their factored form using the leading term, the zeroes and the sign, and how the graph behaves at simple and multiple zeroes.
Behaviour for large x
Polynomial graphs are continuous and smooth. For large $|x|$ the leading term swamps all the others, so the leading term alone decides where the two ends of the graph go.
| Leading coefficient positive | Leading coefficient negative | |
|---|---|---|
| Even degree | both ends up | both ends down |
| Odd degree | down on the left, up on the right | up on the left, down on the right |
Simple and multiple zeroes
If $(x - a)^m$ is a factor of $P(x)$ but $(x - a)^{m+1}$ is not, then $a$ is a zero of multiplicity $m$. Multiplicity $1$ is a simple zero; multiplicity $2$ or more is a multiple (repeated) zero.
Change the multiplicities and watch the graph at each zero. The degree is m + n, which also decides where the ends go.
Which values of $m$ and $n$ make both ends of the graph point upward?
Sketching from factors
Sketch $y = -(x + 1)^2(x - 3)$.
Sketch $y = x^3(x - 2)^2$.
As $x \to \infty$, $y = -2x^4 + x^3 + 5$:
The leading term $-2x^4$ is large and negative.
At a zero of multiplicity $2$, the graph:
Even multiplicity: no sign change.
Find the $y$-intercept of $y = -(x + 1)^2(x - 3)$.
$-(1)(-3) = 3$.
What is the multiplicity of the zero $x = 0$ of $y = x^3(x - 2)^2$?
The factor $x$ appears three times.
Find the degree of $y = x^3(x - 2)^2$.
$3 + 2$.
An odd-degree polynomial with a positive leading coefficient goes:
Like $y = x^3$.
For $y = x^3(x - 2)^2$, where is $y < 0$?
The sign only changes at the triple zero $0$.
The graph of $y = (x - 4)^3$ at $x = 4$:
Multiplicity $3$ is odd, and at least $3$.
How many distinct $x$-intercepts does $y = (x + 1)^2(x - 3)^3$ have?
$-1$ and $3$.
Which equation could match a quartic that touches the axis at $x = 1$ and crosses at $x = -2$ and $x = 3$?
Double zero at $1$, simple zeroes at $-2$ and $3$, degree $4$.
New numbers every time. Keep going until you get five in a row.
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