Arrangements with identical elements
Count arrangements of objects where some are identical by dividing by the arrangements of each identical group, including words with repeated letters and patterns of two kinds of object.
Dividing out the repeats
The letters of TOOT give only $6$ different words, not $4! = 24$, because swapping the two Ts, or the two Os, gives the same word. Each word was counted $2! \times 2! = 4$ times.
How many arrangements are there of the letters of BANANA?
Two kinds of object
Six women and four men queue at a bus stop. How many patterns of men and women are possible?
With restrictions
How many arrangements of SOCKS have the two Ss together?
How many arrangements are there of BANANA?
$\dfrac{6!}{3!\,2!}$.
How many arrangements are there of TOOT?
$\dfrac{4!}{2!\,2!}$.
Six women and four men queue. How many patterns of men and women are possible?
$\dfrac{10!}{6!\,4!}$.
In a queue of ten adults, how many patterns of men and women are possible (any numbers of each)?
Each place is M or W: $2^{10}$.
How many arrangements are there of SOCKS?
$\dfrac{5!}{2!}$.
How many arrangements of SOCKS have the two Ss together?
$4!$ with SS as one block.
How many arrangements are there of MISSISSIPPI?
$\dfrac{11!}{4!\,4!\,2!}$.
The digits $1, 1, 1, 2, 2, 3$ form six-digit numbers. How many are possible?
$\dfrac{6!}{3!\,2!}$.
Eight balls, $7$ red and $1$ white, are lined up. The number of arrangements is:
Only the position of the white ball matters: $\dfrac{8!}{7!}$.
New numbers every time. Keep going until you get five in a row.
Coaching Centre