Using the general term
The general term T(k+1) = nCk a^(n−k) b^k, finding a particular coefficient, the term independent of x, and the greatest coefficient using the ratio of consecutive terms.
The general term
A particular coefficient
Find the coefficient of $x^5$ in $(2x - 1)^8$.
The term independent of x
Find the term independent of $x$ in $\left(x^2 + \dfrac2x\right)^6$.
The greatest coefficient
To find the largest coefficient, compare each coefficient $t_k$ with the next one, using the ratio $\dfrac{t_{k+1}}{t_k}$. The coefficients increase while the ratio is greater than $1$.
Find the greatest coefficient in the expansion of $(1 + 2x)^7$.
Find the coefficient of $x^5$ in $(2x - 1)^8$.
${}^8C_3 \times 2^5 \times (-1)^3$.
Find the term independent of $x$ in $\left(x^2 + \dfrac2x\right)^6$.
$k = 4$: $15 \times 16$.
Find the greatest coefficient in $(1 + 2x)^7$.
$t_5 = 21 \times 32$.
In $(a + b)^n$, the general term $T_{k+1}$ is:
The powers add to $n$.
For $\left(x^2 + \dfrac2x\right)^6$, which value of $k$ gives the constant term?
$12 - 3k = 0$.
Find the coefficient of $x^2$ in $\left(x + \dfrac1x\right)^5$.
The power is $5 - 2k$, which is always odd, so there is no $x^2$ term.
Find the coefficient of $x^3$ in $(1 + 2x)^6$.
${}^6C_3 \times 2^3 = 20 \times 8$.
$\dfrac{{}^nC_{k+1}}{{}^nC_k} = $
Cancel the factorials.
How many terms does the expansion of $(1 + 2x)^6$ have?
$n + 1$.
Find the term independent of $x$ in $\left(x - \dfrac2x\right)^6$.
$k = 3$: ${}^6C_3 \times (-2)^3 = 20 \times (-8)$.
New numbers every time. Keep going until you get five in a row.
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