Factorial notation
The definition of n!, why 0! = 1, unrolling factorials, and simplifying and cancelling expressions with factorials.
The definition
| $n$ | 0 | 1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 |
|---|---|---|---|---|---|---|---|---|---|
| $n!$ | 1 | 1 | 2 | 6 | 24 | 120 | 720 | 5040 | 40 320 |
Factorials grow extremely fast: $10! = 3\,628\,800$ and $20!$ has $19$ digits. That is why we cancel them rather than evaluate them.
Unrolling and cancelling
Evaluate $\dfrac{10!}{7!}$.
Simplify $\dfrac{(n + 1)!}{(n - 1)!}$.
Write $\dfrac{1}{5!} + \dfrac{1}{6!}$ as a single fraction, and simplify $\dfrac{n!}{(n - 2)!} = 42$ to solve for $n$.
Evaluate $5!$.
$5 \times 4 \times 3 \times 2 \times 1$.
Evaluate $0!$.
By definition, so that $1! = 1 \times 0!$ works.
Evaluate $\dfrac{10!}{7!}$.
$10 \times 9 \times 8$.
Evaluate $\dfrac{8!}{6!\,2!}$.
$\dfrac{8!}{6!} = 8 \times 7 = 56$, then divide by $2! = 2$ to get $28$.
$\dfrac{(n + 1)!}{(n - 1)!} = $
Unroll $(n + 1)!$ twice.
Solve $\dfrac{n!}{(n - 2)!} = 42$.
$n(n - 1) = 42$.
$n! = $
Unrolling once.
Write $\dfrac{1}{5!} + \dfrac{1}{6!}$ as a single fraction.
$\dfrac{6 + 1}{6!}$.
Which is true?
Only unrolling is valid.
Evaluate $7!$.
$7 \times 720$.
New numbers every time. Keep going until you get five in a row.
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