Three-dimensional space
Coordinates in three dimensions, right-handed axes, the coordinate planes, distances and midpoints in space, and the equation of a sphere.
Coordinates in space
Three mutually perpendicular axes meet at the origin. They are drawn right-handed: curl the fingers of your right hand from the positive $x$-axis to the positive $y$-axis, and your thumb points along the positive $z$-axis. Each point has coordinates $(x, y, z)$.
The three coordinate planes are the $xy$-plane ($z = 0$), the $yz$-plane ($x = 0$) and the $xz$-plane ($y = 0$). More generally, $z = 3$ is the horizontal plane $3$ units above the $xy$-plane.
Distance and midpoint
The distance formula comes from Pythagoras' theorem used twice, as for the diagonal of a rectangular box.
Find the distance from $A(1, -2, 3)$ to $B(3, 2, -1)$, and the midpoint of $AB$.
Find the length of the longest diagonal of a $2 \times 3 \times 6$ box.
Spheres
Find the centre and radius of $x^2 + y^2 + z^2 - 4x + 6z = 3$.
Find the distance from $A(1, -2, 3)$ to $B(3, 2, -1)$.
$\sqrt{4 + 16 + 16}$.
Find the midpoint of the same points. Enter it as $x, y, z$.
Average each coordinate.
Find the length of the longest diagonal of a $2 \times 3 \times 6$ box.
$\sqrt{4 + 9 + 36}$.
Find the distance from the origin to $(1, 2, 2)$.
$\sqrt{1 + 4 + 4}$.
Find the radius of $x^2 + y^2 + z^2 - 4x + 6z = 3$.
$(x - 2)^2 + y^2 + (z + 3)^2 = 16$.
Find the distance from $(3, 4, 7)$ to the $xy$-plane.
The $z$-coordinate gives the height above $z = 0$.
The $yz$-plane has equation:
Every point on it has $x = 0$.
The sphere $(x - 1)^2 + (y + 2)^2 + z^2 = 9$ has centre:
Change the signs inside the brackets.
In right-handed axes, curling the fingers from the positive $x$-axis to the positive $y$-axis makes the thumb point along:
That is the right-hand rule.
New numbers every time. Keep going until you get five in a row.
Coaching Centre