Differential equations and their solutions
What a differential equation is, its order, checking that a function is a solution, general and particular solutions, families of solution curves, and using initial conditions to find constants.
What is a differential equation?
A differential equation (DE) is an equation involving a derivative, such as $\dfrac{dy}{dx} = 2x$ or $\dfrac{d^2y}{dx^2} + y = 0$. Its order is the order of the highest derivative in it.
A solution is a function that makes the equation true. To check one, substitute it and its derivatives into both sides.
Show that $y = \sin x$ is a solution of $\dfrac{d^2y}{dx^2} + y = 0$.
General and particular solutions
The general solution contains arbitrary constants and describes a whole family of curves. A first-order DE usually needs one constant, and a second-order DE two. An initial condition, such as $y = 3$ when $x = 0$, picks out one particular solution.
Every curve y = x² + C solves dy/dx = 2x. The initial condition chooses which one.
Which value of $C$ gives the curve through $(1, 4)$?
Solve $\dfrac{dy}{dx} = 6x^2 - 4x$, given that $y = 5$ when $x = 1$.
Find $b$ and $c$ so that $y = e^{3x} + bx + c$ is a solution of $\dfrac{dy}{dx} = 3y - 18x$.
What is the order of $\dfrac{d^2y}{dx^2} + 3\dfrac{dy}{dx} = x$?
The highest derivative is the second.
$y = e^{3x}$ is a solution of $\dfrac{dy}{dx} = ky$. Find $k$.
$\dfrac{dy}{dx} = 3e^{3x} = 3y$.
$y = x^2 + C$ passes through $(1, 4)$. Find $C$.
$4 = 1 + C$.
Solve $\dfrac{dy}{dx} = 6x^2$ with $y = 1$ when $x = 0$, then find $y$ when $x = 1$.
$y = 2x^3 + 1$.
In Example 3, find $b$.
$3b - 18 = 0$.
How many arbitrary constants does the general solution of a second-order DE usually have?
One for each integration.
Which is a solution of $\dfrac{d^2y}{dx^2} + y = 0$?
$\dfrac{d^2y}{dx^2} = -\cos x$.
The initial condition in a DE problem is used to:
It picks out one particular solution.
New numbers every time. Keep going until you get five in a row.
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