Components of vectors
The unit vectors i and j, components and column vector notation, magnitude and direction from components, unit vectors, operations with components, position vectors, and vectors between two points.
Components
Let $\underset{\sim}{i}$ and $\underset{\sim}{j}$ be the unit vectors in the directions of the positive $x$- and $y$-axes. Every vector in the plane can be written uniquely as $$\underset{\sim}{u} = x\underset{\sim}{i} + y\underset{\sim}{j} = \begin{pmatrix} x \\ y \end{pmatrix}.$$ The numbers $x$ and $y$ are its components. Vectors are added, subtracted and multiplied by scalars component by component.
Here $\theta$ is the angle from the positive $x$-axis. Check the quadrant from the signs of $x$ and $y$. Going the other way, a vector of length $r$ at angle $\theta$ is $r(\cos\theta\,\underset{\sim}{i} + \sin\theta\,\underset{\sim}{j})$.
$\underset{\sim}{u} = 3\underset{\sim}{i} - 4\underset{\sim}{j}$. Find $|\underset{\sim}{u}|$ and the unit vector $\hat{u}$ in the direction of $\underset{\sim}{u}$.
Write a vector of length $10$ at $150^\circ$ to the positive $x$-axis in component form.
Position vectors
The position vector of a point $A$ is $\underset{\sim}{a} = \overrightarrow{OA}$. Then $$\overrightarrow{AB} = \underset{\sim}{b} - \underset{\sim}{a},$$ "head minus tail".
$A = (1, 2)$ and $B = (4, 6)$. Find $\overrightarrow{AB}$ and the distance $AB$.
Find $|3\underset{\sim}{i} - 4\underset{\sim}{j}|$.
$\sqrt{9 + 16}$.
Find $|{-5}\underset{\sim}{i} + 12\underset{\sim}{j}|$.
$\sqrt{25 + 144}$.
$A = (1, 2)$ and $B = (4, 6)$. Find the components of $\overrightarrow{AB}$. Enter them as $x, y$.
Head minus tail.
For the same points, find the components of $\overrightarrow{BA}$.
The opposite vector.
$\underset{\sim}{u} = \begin{pmatrix} 2 \\ 1 \end{pmatrix}$ and $\underset{\sim}{v} = \begin{pmatrix} 3 \\ -2 \end{pmatrix}$. Find the components of $2\underset{\sim}{u} + \underset{\sim}{v}$. Enter them as $x, y$.
$\begin{pmatrix} 4 + 3 \\ 2 - 2 \end{pmatrix}$.
Find the $x$-component of the unit vector in the direction of $3\underset{\sim}{i} - 4\underset{\sim}{j}$.
$\tfrac35$.
A vector has length $10$ at $150^\circ$ to the positive $x$-axis. Find its $y$-component.
$10\sin 150^\circ$.
The direction of $-2\underset{\sim}{i} + 2\underset{\sim}{j}$, measured from the positive $x$-axis, is:
Second quadrant, at $45^\circ$ to the negative $x$-axis.
A unit vector has:
That is the definition.
New numbers every time. Keep going until you get five in a row.
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