Applications of differential equations
Modelling with differential equations, including exponential growth and decay, motion with air resistance and terminal velocity, mixing problems, the spread of a rumour or disease with the logistic model, and interpreting solutions.
Common models
| Situation | DE | Behaviour |
|---|---|---|
| Rate proportional to the amount | $\dfrac{dN}{dt} = kN$ | Exponential growth or decay |
| Rate proportional to the difference from a fixed value | $\dfrac{dN}{dt} = k(N - P)$ | Approaches $P$ (for $k \lt 0$) |
| Growth limited by a capacity | $\dfrac{dP}{dt} = kP\left(1 - \dfrac{P}{K}\right)$ | S-shaped, approaches $K$ |
Motion with air resistance
A skydiver falls from rest, and $\dfrac{dv}{dt} = 10 - 0.5v$. Find $v$ as a function of $t$ and the terminal velocity.
Mixing problems
A tank holds $100$ L of pure water. Brine with $2$ g/L of salt flows in at $5$ L/min, and the mixture flows out at $5$ L/min. Find the amount of salt $S$ after $t$ minutes.
Spread of a rumour
A rumour spreads through a school of $800$ students so that $\dfrac{dN}{dt} = 0.001N(800 - N)$. When is it spreading fastest?
For $\dfrac{dv}{dt} = 10 - 0.5v$, find the terminal velocity.
$\dfrac{dv}{dt} = 0$ when $v = 20$.
In Example 1, find $v$ when $t = 2\ln 2$.
$20(1 - e^{-\ln 2}) = 20 \times \tfrac12$.
In Example 2, how much salt is in the tank in the long run, in grams?
$S \to 200$.
In Example 2, find $S$ when $t = 20\ln 2$.
$200(1 - \tfrac12)$.
In Example 3, how many students know the rumour when it spreads fastest?
Half of $800$.
A disease spreads so that $N = \dfrac{1000}{1 + 999e^{-t}}$. How many people are infected at $t = 0$?
$\dfrac{1000}{1000}$.
"The rate of decay is proportional to the amount present" gives:
Here $k \gt 0$ and the minus sign gives decay.
In a mixing problem, the outflow rate of salt depends on:
Rate out $=$ concentration $\times$ outflow.
New numbers every time. Keep going until you get five in a row.
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