Sketching polynomials from their zeroes
Reviewing the factor theorem, sketching a polynomial from its linear factors, the behaviour of the graph at zeroes of odd and even multiplicity, and the leading term at the far left and right.
This builds on the polynomials chapter from Year 11 Extension 1.
The factor theorem
$P(\alpha) = 0$ exactly when $(x - \alpha)$ is a factor of $P(x)$. A zero $\alpha$ has multiplicity $m$ when $(x - \alpha)^m$ is a factor but $(x - \alpha)^{m+1}$ is not.
Shape at a zero
| Multiplicity | Behaviour of the graph |
|---|---|
| $1$ (single) | Crosses the axis, like a line. |
| $2$ (double) | Touches the axis and turns back, like a parabola. |
| $3$ (triple) | Crosses the axis while flattening out: a horizontal point of inflection. |
In general, an odd multiplicity crosses and an even multiplicity touches. Far to the left and right, the graph follows its leading term.
y = 0.3(x + 1)ⁿ(x − 2). At x = −1, the graph crosses when n is odd and touches when n is even.
Which value of $n$ gives a horizontal point of inflection at $x = -1$?
Sketch $y = (x + 1)^2(x - 2)$.
Find a cubic with a double zero at $x = 3$, a single zero at $x = -1$, and $y$-intercept $18$.
Find the $y$-intercept of $y = (x + 1)^2(x - 2)$.
$1 \times (-2)$.
A cubic is $a(x - 3)^2(x + 1)$ with $y$-intercept $18$. Find $a$.
$9a = 18$.
What is the multiplicity of the zero $x = 4$ of $(x - 4)^3(x + 1)$?
The power of $(x - 4)$.
What is the degree of $(x - 1)^2(x + 2)^3$?
$2 + 3$.
At a double zero, the graph:
Like $y = x^2$ at the origin.
At a triple zero, the graph:
Like $y = x^3$ at the origin.
As $x \to -\infty$, $y = -(x - 1)^2(x + 3)$:
The leading term is $-x^3$.
Which has the graph touching the $x$-axis at $x = 2$?
A double zero at $x = 2$.
New numbers every time. Keep going until you get five in a row.
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