The unitary method and reverse percentages
Using the unitary method to find the original amount before a percentage change, and other percentage problems.
Find one unit first
$15\%$ of a number is $45$. Find the number.
Finding the original amount
After a $20\%$ discount, a jacket costs $\$96$. What was the original price?
A price including $10\%$ GST is $\$341$. Find the price before GST.
$15\%$ of a number is $45$. Find the number.
$1\% = 3$.
After a $20\%$ discount a jacket costs $\$96$. Find the original price.
$80\% = 96$.
Including $10\%$ GST a price is $\$341$. Find the price before GST.
$341 \div 1.1$.
$40\%$ of a number is $320$. Find the number.
$320 \div 0.4$.
After a $25\%$ pay rise, a wage is $\$75$ per hour. Find the original hourly wage.
$125\% = 75$, so $100\% = 60$.
A shop sells $30\%$ of its stock, which is $75$ items. How many items did it start with?
$75 \div 0.3$.
After a $10\%$ decrease, a value is $45$. Find the original value.
$90\% = 45$.
After $25\%$ off, a price is $\$60$. The original price is:
$75\% = 60$, so $1\% = 0.8$.
New numbers every time. Keep going until you get five in a row.
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