Equations with brackets and pronumerals on both sides
Expanding brackets to solve equations, and collecting pronumerals on one side when they appear on both sides.
Brackets
Solve $3(x - 4) = 15$.
$3x - 12 = 15$
Expand
$3x = 27$, so $x = 9$
Pronumerals on both sides
Solve $5x + 3 = 2x + 18$.
$3x + 3 = 18$
Subtract 2x
$3x = 15$, so $x = 5$
Solve $2(x + 5) = 4(x - 1)$.
$2x + 10 = 4x - 4$
$10 = 2x - 4$
Subtract 2x
$14 = 2x$, so $x = 7$
First step with brackets
Expand (or divide by the number outside).
$x$ on both sides
Subtract the smaller $x$ term from both sides.
$7x = 3x + 20$
$x = 5$
Solve $3(x - 4) = 15$.
$x - 4 = 5$.
Solve $5x + 3 = 2x + 18$.
$3x = 15$.
Solve $2(x + 5) = 4(x - 1)$.
$2x + 10 = 4x - 4$.
Solve $7x = 3x + 20$.
$4x = 20$.
Solve $4(x + 5) = 8$.
$x + 5 = 2$.
Solve $6x - 7 = 2x + 9$.
$4x = 16$.
Solve $3(2x - 1) + 2 = 11$.
$6x - 1 = 11$.
Solve $x + 8 = 4 - x$.
$2x = -4$.
New numbers every time. Keep going until you get five in a row.
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