Rates and concentration
Rates with two different units, concentration as a rate (g/L, mg/mL, % w/v and % v/v), diluting a solution, and drip rates for intravenous fluids.
A rate tells you how much of one thing there is for each unit of another: kilometres per hour, dollars per kilogram, milligrams per millilitre. Concentration is just a rate that measures how much of a substance is packed into each unit of liquid. Pharmacists, nurses, farmers and pool owners all work with it.
Revise: unit rates and converting km/h to m/s are in Year 11 Units, rates and conversions.
Converting rates
A rate has two units, so a conversion may need two steps: one for the top unit and one for the bottom. Change one unit at a time and ask whether the number should get bigger or smaller.
A tap leaks $45$ mL per minute. Write this as litres per day.
Concentration
$\text{concentration} = \dfrac{\text{amount of substance}}{\text{volume of solution}}$
$\%\ \text{w/v}$ = grams per $100$ mL. $\%\ \text{v/v}$ = mL per $100$ mL.
So $\text{amount} = \text{concentration} \times \text{volume}$.
"w/v" means weight over volume: a $0.9\%$ w/v saline drip has $0.9$ g of salt in every $100$ mL. "v/v" means volume over volume: a drink labelled $5\%$ v/v has $5$ mL of alcohol in every $100$ mL.
How much salt is in a $250$ mL bag of $0.9\%$ w/v saline?
A pool chemical is sold as $12.5$ g/L. How many grams are in a $20$ L drum, and what is the strength in mg/mL?
Diluting
When you add water, the amount of substance does not change. It is just spread through more liquid, so the concentration falls. That single idea solves every dilution problem: work out the amount, then divide by the new volume.
amount before = amount after, so $C_1 V_1 = C_2 V_2$
A cleaner mixes $40$ mL of $5\%$ w/v disinfectant with $360$ mL of water. What is the new concentration?
Check Example 4 on Disinfectant. Then predict the strength if you add $760$ mL of water instead of $360$, and test it. Can you make exactly $1\%$ w/v from $5\%$ stock? Next switch to Medicine and find how much water turns $10$ mL of $50$ mg/mL stock into $5$ mg/mL.
Drip rates
In hospitals, fluid is given through a drip. A pump is set in mL per hour, while a gravity drip is counted in drops per minute. The tubing's drop factor says how many drops make $1$ mL.
$\text{drops/min} = \dfrac{\text{volume} \times \text{drop factor}}{\text{time}}$
with volume in mL, drop factor in drops/mL and time in minutes.
A patient is to receive $1200$ mL over $10$ hours through tubing with a drop factor of $20$ drops/mL. Find the rate in mL/h and in drops per minute.
Your turn
How much water must be added to $50$ mL of $20\%$ w/v fertiliser to make a $2\%$ w/v solution?
Show the working
Amount: $20 \times 50 \div 100 = 10$ g. For $2\%$, $10$ g must be in $10 \div 2 \times 100 = 500$ mL. Water to add: $500 - 50 = 450$ mL.
A tap leaks $45$ mL per minute. How many litres is that per day?
$45 \times 60 \times 24 = 64{,}800$ mL $= 64.8$ L.
How many grams of salt are in $250$ mL of $0.9\%$ w/v saline?
$0.9$ g per $100$ mL, so $0.9 \times 250 \div 100 = 2.25$ g.
A $375$ mL can is $5\%$ v/v alcohol. How many mL of alcohol does it contain?
$5$ mL per $100$ mL, so $5 \times 375 \div 100 = 18.75$ mL.
$3$ g/L is the same as:
$3$ g $= 3000$ mg and $1$ L $= 1000$ mL, so $3000 \div 1000 = 3$ mg/mL.
$40$ mL of $5\%$ w/v disinfectant is mixed with $360$ mL of water. What is the new concentration, as a % w/v?
Amount $= 5 \times 40 \div 100 = 2$ g. Volume $= 400$ mL. $2 \div 400 \times 100 = 0.5$.
When water is added to a solution, which stays the same?
Water adds volume, not substance, so the amount stays the same and the concentration falls.
How many mL of water must be added to $50$ mL of $20\%$ w/v fertiliser to make $2\%$ w/v?
Amount $= 10$ g. $2\%$ needs $10 \div 2 \times 100 = 500$ mL. $500 - 50 = 450$ mL of water.
$10$ mL of $50$ mg/mL stock is diluted to $5$ mg/mL. How many mL of water are added?
$C_1V_1 = C_2V_2$: $50 \times 10 = 5 \times V_2$, so $V_2 = 500 \div 5 = 100$ mL in total. Water added $= 100 - 10 = 90$ mL.
Exam style: $1200$ mL is to be given over $10$ hours with a drop factor of $20$ drops/mL. Find the drip rate in drops per minute.
$1200 \times 20 = 24{,}000$ drops over $600$ minutes. $24{,}000 \div 600 = 40$ drops/min.
Exam style: For the same drip, what is the rate in mL per hour?
$1200 \div 10 = 120$ mL/h.
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