The definite integral and its properties
Definite integrals as sums of signed areas, integrals of odd and even functions over symmetric intervals, dissecting the interval, reversing the limits, sums and multiples of functions, and inequalities.
Signed areas
When the curve is below the $x$-axis, the integral comes out negative. In general, $\displaystyle\int_a^b f(x)\,dx$ is the area above the axis minus the area below it.
Evaluate $\displaystyle\int_0^3 (x - 1)\,dx$ and explain the answer with areas.
Odd and even functions
Orange areas count as positive and blue as negative. For an odd function they are mirror images, so they cancel exactly.
Does the total area also come to $0$?
Evaluate $\displaystyle\int_{-1}^{1} (x^4 + x^2)\,dx$.
Rules for definite integrals
| Dissection | $\displaystyle\int_a^b f\,dx + \int_b^c f\,dx = \int_a^c f\,dx$ |
| Zero width | $\displaystyle\int_a^a f\,dx = 0$ |
| Reversing | $\displaystyle\int_b^a f\,dx = -\int_a^b f\,dx$ |
| Sums and multiples | $\displaystyle\int_a^b \big(kf + g\big)\,dx = k\int_a^b f\,dx + \int_a^b g\,dx$ |
| Inequalities | If $f(x) \le g(x)$ on $[a, b]$, then $\displaystyle\int_a^b f\,dx \le \int_a^b g\,dx$ |
Given $\displaystyle\int_0^3 f(x)\,dx = 5$ and $\displaystyle\int_0^1 f(x)\,dx = 2$, find $\displaystyle\int_1^3 f(x)\,dx$, $\;\displaystyle\int_3^0 f(x)\,dx$ and $\displaystyle\int_0^3 \big(2f(x) + 1\big)\,dx$.
Evaluate $\displaystyle\int_0^3 (x - 1)\,dx$.
$\tfrac92 - 3$.
Evaluate $\displaystyle\int_{-2}^{2} (x^3 - 4x)\,dx$.
The integrand is odd.
Evaluate $\displaystyle\int_{-1}^{1} (x^4 + x^2)\,dx$.
$2\left(\tfrac15 + \tfrac13\right)$.
$\displaystyle\int_0^3 f = 5$ and $\displaystyle\int_0^1 f = 2$. Find $\displaystyle\int_1^3 f$.
$5 - 2$.
For the same $f$, find $\displaystyle\int_3^0 f(x)\,dx$.
Reversing the limits changes the sign.
For the same $f$, find $\displaystyle\int_0^3 \big(2f(x) + 1\big)\,dx$.
$10 + 3$.
Evaluate $\displaystyle\int_{-2}^{2} x^2\,dx$.
$2 \times \tfrac83$.
$\displaystyle\int_4^4 (x^3 + 7)\,dx = $
An interval of zero width.
A negative definite integral means:
Areas below the axis count as negative.
New numbers every time. Keep going until you get five in a row.
Coaching Centre