The standard normal distribution
The standard normal distribution with mean 0 and standard deviation 1, its bell-shaped PDF, finding probabilities with a table or calculator, symmetry, and quartiles.
The bell curve
The standard normal variable $Z$ has mean $0$ and standard deviation $1$. Its curve is bell-shaped, symmetric about $z = 0$, has its maximum at $z = 0$, and gets very close to the axis beyond $z = \pm 3$. The total area is $1$.
Slide a. At a = 0 the shaded area is exactly one half, by symmetry.
At $a = 1$ the shaded area is about $0.8413$. Where is the remaining $0.1587$?
Finding probabilities
There is no simple primitive for $\phi$, so use a table or calculator for $P(Z \le a)$. The table only gives areas to the left, so use these facts for everything else.
| $a$ | 0.5 | 1 | 1.5 | 2 |
|---|---|---|---|---|
| $P(Z \le a)$ | 0.6915 | 0.8413 | 0.9332 | 0.9772 |
Find $P(Z \gt 1)$ and $P(Z \lt -1)$.
Find $P(-1 \lt Z \lt 2)$.
Find the upper quartile of $Z$.
Find $P(Z \gt 1)$, given $P(Z \le 1) = 0.8413$.
$1 - 0.8413$.
Find $P(Z \lt -1)$.
Symmetry.
Find $P(-1 \lt Z \lt 2)$, given $P(Z \le 2) = 0.9772$.
$0.9772 - 0.1587$.
Find $P(-1 \lt Z \lt 1)$.
$0.8413 - 0.1587$.
Find $P(Z \gt 1.5)$, given $P(Z \le 1.5) = 0.9332$.
$1 - 0.9332$.
Find $P(Z \gt 0)$.
Half the area is on each side.
Find $P(Z \lt -0.5)$, given $P(Z \le 0.5) = 0.6915$.
$1 - 0.6915$.
The standard normal curve has its maximum at:
It is symmetric about $0$.
The lower quartile of $Z$ is about:
The mirror image of the upper quartile.
New numbers every time. Keep going until you get five in a row.
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