Differentiating exponential functions
Differentiating e^f(x) with the chain rule, and functions involving e^x with the product and quotient rules.
The chain rule
In words: the exponential stays the same, and it is multiplied by the derivative of the index.
Differentiate $y = e^{x^2 + 1}$.
Differentiate $y = (e^x + 1)^3$.
Product and quotient rules
Differentiate $y = x^2e^x$.
Differentiate $y = \dfrac{e^x}{x}$.
$\dfrac{d}{dx}e^{x^2 + 1} = $
Multiply by the derivative of the index.
$\dfrac{d}{dx}x^2e^x = $
Product rule.
$\dfrac{d}{dx}\dfrac{e^x}{x} = $
$\dfrac{vu' - uv'}{v^2}$.
$\dfrac{d}{dx}(e^x + 1)^3 = $
Chain rule: the derivative of the inside is $e^x$.
Find the gradient of $y = xe^x$ at $x = 0$.
$(x + 1)e^x$ at $x = 0$.
Find the gradient of $y = e^{x^2}$ at $x = 1$. Type $e$ as e.
$2xe^{x^2}$ at $x = 1$.
Find the gradient of $y = e^{-x^2}$ at $x = 0$.
$-2xe^{-x^2}$ at $x = 0$.
$\dfrac{d}{dx}\big(e^{2x} - e^{-2x}\big) = $
The second term gives $-(-2)e^{-2x}$.
$\dfrac{d}{dx}\sqrt{e^x} = $
$\sqrt{e^x} = e^{\frac{x}{2}}$.
New numbers every time. Keep going until you get five in a row.
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