Second and higher derivatives
The second, third and higher derivatives of a function, their notations, and finding successive derivatives of polynomials, negative powers and composite functions.
Differentiating again
The derivative $f'(x)$ is itself a function, so it can be differentiated. The result is the second derivative, which measures how fast the gradient is changing.
| Function notation | Leibniz notation | |
|---|---|---|
| first | $f'(x)$ or $y'$ | $\dfrac{dy}{dx}$ |
| second | $f''(x)$ or $y''$ | $\dfrac{d^2y}{dx^2}$ |
| third | $f'''(x)$ or $y'''$ | $\dfrac{d^3y}{dx^3}$ |
Find all the derivatives of $y = x^5 - 2x^3$.
Find the first three derivatives of $y = \dfrac{1}{x}$.
Find $f''(x)$ for $f(x) = (2x + 1)^4$.
For $f(x) = x^5 - 2x^3$, find $f''(1)$.
$20 - 12$.
For $y = \dfrac1x$, find $y'''$ at $x = 1$.
$-6x^{-4}$.
For $f(x) = (2x + 1)^4$, find $f''(0)$.
$48 \times 1^2$.
Find the fifth derivative of $x^4$.
The fourth derivative is the constant $24$.
$\dfrac{d^2}{dx^2}\,x^n = $
Differentiate $nx^{n-1}$.
For $f(x) = x^3$, find $f''(2)$.
$f''(x) = 6x$.
For $y = \sqrt{x}$, find $y''$ at $x = 4$.
$y'' = -\tfrac14 x^{-\frac32} = -\tfrac14 \times \tfrac18$.
For $y = x^2$, $\left(\dfrac{dy}{dx}\right)^2 = $
$(2x)^2$. This is not the second derivative.
For $y = x^4$, find $\dfrac{d^4y}{dx^4}$.
$4 \times 3 \times 2 \times 1$.
New numbers every time. Keep going until you get five in a row.
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