Expanding brackets
Using the distributive law to expand brackets, including negative terms outside the bracket, and simplifying the result.
The distributive law
Distributive law
$$a(b + c) = ab + ac$$Multiply the term outside by every term inside.
The bracket form and the expanded form draw exactly the same line, so they are equivalent.
Expand $4(2x - 3)$.
$4 \times 2x - 4 \times 3 = 8x - 12$
Expand $-3(a - 5)$.
$-3 \times a = -3a$ and $-3 \times (-5) = +15$
$= -3a + 15$
Expand, then simplify
Expand and simplify $2(x + 4) + 3(x - 1)$.
$2x + 8 + 3x - 3$
$= 5x + 5$
$a(b + c)$
$ab + ac$
$-2(x - 4)$
$-2x + 8$
$x(x + 3)$
$x^2 + 3x$
Expand $4(2x - 3)$.
Multiply both terms by $4$.
Expand $-3(a - 5)$.
$-3 \times -5 = 15$.
Expand and simplify $2(x + 4) + 3(x - 1)$.
$2x + 8 + 3x - 3$.
Expand $x(x + 3)$.
$x \times x = x^2$.
Expand $5(2y - 7)$.
$10y - 35$.
Expand $-2(x - 4)$.
$-2 \times -4 = 8$.
Expand and simplify $3(a + 5) - (a + 4)$.
$3a + 15 - a - 4$.
Expand $3m(2m - 3)$.
$6m^2 - 9m$.
New numbers every time. Keep going until you get five in a row.
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