Coordinate geometry of lines
Equation of a line from two points, general form ax + by + c = 0, parallel and perpendicular lines, distance, midpoint and collinear points.
General form
The general form of a line is $ax + by + c = 0$ with whole-number $a$, $b$, $c$ and $a > 0$. For example, $y = \tfrac{4}{3}x + 1$ becomes $4x - 3y + 3 = 0$.
Find the line perpendicular to $3x + 4y = 12$ through $(0, 1)$.
Are $(1, 1)$, $(2, 3)$ and $(4, 7)$ collinear (on one line)?
Line through $(-1, 2)$ and $(3, 10)$: $y = $ ?
$m = 2$.
Gradient perpendicular to $3x + 4y = 12$?
Original $m = -\tfrac{3}{4}$.
Midpoint of $(-2, 7)$ and $(6, -1)$?
$(4/2, 6/2)$.
Exact distance from $(-2, 7)$ to $(6, -1)$? Type like 8sqrt(2).
$\sqrt{64 + 64} = \sqrt{128}$.
Are $(1, 1)$, $(2, 3)$, $(4, 7)$ collinear?
Both gradients are $2$.
Gradient of $2x + 5y - 10 = 0$?
$y = -\tfrac{2}{5}x + 2$.
$y = \tfrac{4}{3}x + 1$ in general form is:
Multiply by $3$: $3y = 4x + 3$.
$y = kx + 2$ is perpendicular to $y = x - 5$. Find $k$.
$k \times 1 = -1$.
New numbers every time. Keep going until you get five in a row.
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